比较 Python 中的两个字典列表。 返回不匹配

Question

I have two lists of dictionaries like below:

incidents = [
    {
        "incidentId": "RWS03_949563",
        "incidentState": "REGISTERED"
    },
    {
        "incidentId": "RWS03_949565",
        "incidentState": "REGISTERED"
    }
]

incidents_db = [
    {
        "incidentId": "RWS03_949563",
        "incidentState": "PENDING"
    },
    {
        "incidentId": "RWS03_949565",
        "incidentState": "PENDING"
    }
]

I want to compare the incidentId with each other and return the non_match. This is my code now, but it returns just the two items, because it is comparing the whole item instead of only the incidentId . What's a good way to do this?

non_match = []
for i in incidents:
    if i not in incidents_db:
        non_match.append(i)

Answer 1

incidents = [
    {
        "incidentId": "RWS03_949563",
        "incidentState": "REGISTERED"
    },
    {
        "incidentId": "RWS03_947565",
        "incidentState": "REGISTERED"
    },
        {
        "incidentId": "RWS02_947565",
        "incidentState": "REGISTERED"
    },
        {
        "incidentId": "RWS05_947565",
        "incidentState": "REGISTERED"
    }
]

incidents_db = [
    {
        "incidentId": "RWS03_949563",
        "incidentState": "PENDING"
    },
    {
        "incidentId": "RWS03_949565",
        "incidentState": "PENDING"
    }
]

for i in incidents:
    c = 0
    for j in incidents_db:
        if j["incidentId"] == i["incidentId"]:
            c+=1
    if c==0:
        incidents_db.append(i)

#output
incidents_db

[{'incidentId': 'RWS03_949563', 'incidentState': 'PENDING'},
 {'incidentId': 'RWS03_949565', 'incidentState': 'PENDING'},
 {'incidentId': 'RWS03_947565', 'incidentState': 'REGISTERED'},
 {'incidentId': 'RWS02_947565', 'incidentState': 'REGISTERED'},
 {'incidentId': 'RWS05_947565', 'incidentState': 'REGISTERED'}]

for i in incidents:
    c = 0
    for j in incidents_db:
        if j["incidentId"] == i["incidentId"]:
            c+=1
    if c==0:
        i["incidentState"] = "PENDING"
        incidents_db.append(i)

#output

[{'incidentId': 'RWS03_949563', 'incidentState': 'PENDING'},
 {'incidentId': 'RWS03_949565', 'incidentState': 'PENDING'},
 {'incidentId': 'RWS03_947565', 'incidentState': 'PENDING'},
 {'incidentId': 'RWS02_947565', 'incidentState': 'PENDING'},
 {'incidentId': 'RWS05_947565', 'incidentState': 'PENDING'}]

Answer 2

If you only want to compare two specific items from the dictionary. Do this:

non_match = []

for incident_dict in incidents:
    for db_dict in incidents_db:
        for key, value in incident_dict.items():
            if not db_dict.get(key, False):
                non_match.append(value)

Answer 3

if you want to compare only " incidentId"

non_match = []
for i in range(0,min(len(incidents),len(incidents_db))):
    if incidents[i].get("incidentId") != incidents_db[i].get("incidentId"):
        non_match.append(incidents[i])
print(non_match)

Answer 4

non_match = []
for a,b in zip(incidents, incidents_db):
    if a.get("incidentId") != b.get("incidentId"):
        non_match.append(a.get("incidentId"))
print(non_match)