两种不同的类型，C#中的一种方法实现

Question

What would be best approach to implement this scenario: There is service method and two types, which differs only on List items type:

public long MyMethod(MyType request) {...}

Also i have two models, which are almost similar:

public class MyType {
    public int amount {get; set;}
    public List<MyDetailsType> details {get; set;}
}

public class MyType2 {
    public int amount {get; set;}
    public List<MyDetailsType2> details {get; set;}
}

How to make this one method

public long MyMethod(MyType request) {...}

work for both request types without overload ? Interface? Abstract class? Virtual? Also the method is called once, so generic type not work, because method need parameter type defined, which i dont know until variable not set.

App flow is as follows:

• Get request
• Request is generated by some conditions to MyType or MyType2
• Call to MyMethod

Method1(SomeType request) {
    var request;
    if(a) {
       request = new MyType();
    } else {
       request = new MyType2();
    }

    MyMethod(request);
}

Answer 1

Here's a possible solution:

public long MyMethod<T>(MyBaseType<T> request) { ... }

public abstract class MyBaseType<T>
{
    public int Amount { get; set; }
    public List<T> Details { get; set; }
}

public class MyType : MyBaseType<MyDetailsType>
{
    // additional code
}

public class MyType2 : MyBaseType<MyDetailsType2>
{
    // additional code
}

---

If no additional code is needed for the derived classes, you can just use one class (without the abstract keyword).

The Method1 code would look something like this:

void Method1(SomeType request)
{
    if (a)
       request = new MyBaseType<MyDetailsType>();
    else
       request = new MyBaseType<MyDetailsType2>();

    MyMethod(request);
}