Java 正则表达式，用于双精度内的任何内容 ** 示例：**文本**

Question

I need the regex for this case scenario:

**This text is bold** this is not **abc123*-#$%&/()** this is not **yes****

So I can have these results separated:

This text is bold
abc123*-#$%&/()
yes**

I have been struggling with this for hours, help.

The most close I have been is this:

\*\*([^\*]\*)\*\*

Actually, I need to use * inside **here(*)** in order to obtain here(*) .

I wanna obtain 123?=)* result from **123?=)*** .

Answer 1

You can use

\*\*([^*]*(?:\*(?!\*)[^*]*)*\**)\*\*

See the regex demo .

An equivalent is (?s)\*\*(.*?)\*\*(?!\*) , see this regex demo (based on Andreas suggestion ). However, this pattern is about 1/3 slower than the previous one.

Details

• \*\* - a ** substring
• ([^*]*(?:\*(?!\*)[^*]*)*\**) - Group 1: any zero or more chars other than * ( [^*]* ) that are followed with zero or more repetitions of a * that is not immediately followed with * (see \*(?!\*) ) and then zero or more non-asterisk chars, and then any amount of asterisks (see the \** at the end of the group pattern)
• \*\* - a ** substring

The (?s)\*\*(.*?)\*\*(?!\*) is similar, the (?s) is a DOTALL inline modifier that makes a . match across lines, and then (.*?) matches and captures into Group 1 any zero or more chars as few as possible, up to the first occurrence of ** text that is not immmediately followed with * .