从 PowerShell 命令执行 SQL 时如何参数化登录

Question

How do we run CREATE LOGIN... against a variable string?

I'm executing the following command:

Invoke-Sqlcmd -ServerInstance $ServerInstance -Database 'master' -Username $DBAdminAccount -Password $DBAdminPassword -Variable $SqlVariables -InputFile $ArtifactStagingDirectory\MasterDBSetup.sql

MasterDBSetup.sql:

....
    IF NOT EXISTS (SELECT name  FROM sys.sql_logins WHERE name = '$(SvcRRRComparisonUser)')
    BEGIN 
        CREATE LOGIN '$(SvcRRRComparisonUser)' WITH PASSWORD = '$(RRRComparisonUserPassword)'
    END
....

How do we run CREATE LOGIN... against $(SvcRRRComparisonUser) ?

Answer 1

In the $SqlVariables :

$SqlVariables = @("SvcRRRComparisonUser='user1',RRRComparisonUserPassword='pass1'")

Then in the SQL file:

IF NOT EXISTS (SELECT name  FROM sys.sql_logins WHERE name = $(SvcRRRComparisonUser)
BEGIN 
    CREATE LOGIN $(SvcRRRComparisonUser) WITH PASSWORD = $(RRRComparisonUserPassword)
END