[英]Filter the maximum from a tuple using Python Lambda function
I have a list of tuples like below:我有一个如下的元组列表:
data = [(0.5, 0, 0), (0.4, 0, 0), (0.6, 0, 0)]
I want to find the maximum value over the first element of each tuple using a lambda
function.我想使用lambda
function 在每个元组的第一个元素上找到最大值。 In this case, the expected result would be 0.6.在这种情况下,预期结果将是 0.6。
I'd usually write this like this:我通常会这样写:
>>> a = [(0.5, 0, 0), (0.4, 0, 0),(0.6, 0, 0)]
>>> max(x for x, y, z in a)
0.6
Since you have the strange requirement to use a lambda function, you can also do由于您有使用 lambda function 的奇怪要求,您也可以这样做
>>> max(a, key=lambda x: x[0])[0]
0.6
However, this is more complicated than necessary, and other than your random requirement there is no reason to do this.但是,这比必要的复杂,除了您的随机要求之外,没有理由这样做。
l = [(0.5, 0, 0), (0.4, 0, 0),(0.6, 0, 0)]
y = max(map(lambda x: x[0], l))
print(y)
>>> 0.6
Usually people want the item (tuple) that contains the maximum first value, rather than just the max first value.通常人们想要包含最大第一个值的项目(元组),而不仅仅是最大第一个值。 This is exactly when having a lambda
is useful:这正是使用lambda
有用的时候:
>>> data = [(0.5, 0, 0), (0.4, 0, 0), (0.6, 0, 0)]
>>> max(data, key=lambda x: x[0])
(0.6, 0, 0)
Or the most simple - if you want only the max first value and not the tuple with the max value - is without a lambda:或者最简单的 - 如果你只想要最大的第一个值而不是具有最大值的元组 - 没有 lambda:
>>> max(x[0] for x in data)
0.6
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.