根据第二个文件的部分名称批量重命名文件

Question

I want to batch rename some file based of Part of Name of other files
let me explain my question with a example, I think its better in this way
I have some file with these name in a folder

sc_gen_08-bigfile4-0-data.txt
signal_1_1-bigfile8.1-0-data.txt

and these file in other folder

sc_gen_08-acaaf2d4180b743b7b642e8c875a9765-1-data.txt
signal_1_1-dacaaf280b743b7b642e8c875a9765-4-data.txt

I want to batch rename first files to name of second files, how can I do this? also file in both first and second folder have common in name

name(common in file in both folder)-[only this part is diffrent in each file]-data.txt

Thanks (sorry if its not a good question for everyone, but its a question for me)

Answer 1

Let's name the original folder as "folder1" and the other folder as "folder2". Then would you please try the following:

#!/bin/bash

folder1="folder1"                       # the original folder name
folder2="folder2"                       # the other folder name

declare -A map                          # create an associative array
for f in "$folder2"/*-data.txt; do      # find files in the "other folder"
    f=${f##*/}                          # remove directory name
    common=${f%%-*}                     # extract the common substring
    map[$common]=$f                     # associate common name with full filename
done

for f in "$folder1"/*-data.txt; do      # find files in the original folder
    f=${f##*/}                          # remove directory name
    common=${f%%-*}                     # extract the common substring
    mv -- "$folder1/$f" "$folder1/${map[$common]}"
                                        # rename the file based on the value in map
done

Answer 2

If your files are all called as you mentioned. I have created the next script.

It is located following the next structure.

root@vm:~/test# ll
folder1/
folder2/
script.sh     

The script is the next:

#Declare folders
folder1=./folder1
folder2=./folder2

#Create new folder if it does not exist
if [ ! -d ./new ]; then
  mkdir ./new;
fi

#Iterate over first directory
for file1 in folder1/*; do
        #Iterate over second directory
        for file2 in folder2/*; do
                #Compare begining of each file, if they match, they will be copied.
                if [[ $(basename $file1 | cut -f1 -d-) == $(basename $file2 | cut -f1 -d-) ]]; then
                    echo $(basename $file1) $(basename $file2) "Match"
                    cp folder1/$(basename $file1) new/$(basename $file2)
                fi
        done
done

It creates a folder called new and will copy all your files there. If you want to delete them, use mv instead. But I didn't want to use mv in the first attempt just in case to get some undesired effect.