[英]Unknown type name in C linked list structure
I got a structure like this in a header file:我在 header 文件中得到了这样的结构:
typedef struct {
LIGNE *precedent;
PERSONNE individu;
LIGNE *suivant;
} LIGNE;
But when I compile, I got this error:但是当我编译时,我得到了这个错误:
error: unknown type name ‘LIGNE’
LIGNE *precedent;
^~~~~
error: unknown type name ‘LIGNE’
LIGNE *suivant;
I don't understand where is the problem.我不明白问题出在哪里。
Put yourself in compilers shoes:把自己放在编译器的鞋子里:
1: typedef struct {
2: LIGNE *precedent;
3: PERSONNE individu;
4: LIGNE *suivant;
5: } LIGNE;
In line 2 you say that you want a pointer to something of type LIGNE
.在第 2 行中,您说您想要一个指向
LIGNE
类型的指针。 That's a problem for compiler since it has no idea what LIGNE
is until line 5. Granted, this is compiler being a little dumb.这对编译器来说是个问题,因为直到第 5 行它才知道
LIGNE
是什么。当然,这是编译器有点笨。 A pointer to anything is the same size, so as far as layout of structure goes, it shouldn't matter.指向任何东西的指针大小相同,因此就结构布局而言,这无关紧要。 However, C compiler wants to know what sort of pointer this.
但是,C 编译器想知道这是什么类型的指针。 As @Gerhardh suggested, you can trick it by prefixing lines 2 and 4 with
struct
.正如@Gerhardh 所建议的那样,您可以通过在第 2 行和第 4 行前加上
struct
来欺骗它。 Compiler sees this and reads it as pointer to structure , suddenly no longer caring that it knows not anything about it.编译器看到这一点并将其作为指向结构的指针读取,突然不再关心它对它一无所知。
This will work这将起作用
typedef struct {
struct LIGNE *precedent;
PERSONNE individu;
struct LIGNE *suivant;
} LIGNE;
As said in the commants and in the Tomo Ceferin 's answer, your compiler has no idea of what LIGNE
is until line 5.正如评论和Tomo Ceferin的回答中所说,您的编译器直到第 5 行才知道
LIGNE
是什么。
One solution would be to typedef your structure before its declaration:一种解决方案是在声明之前对您的结构进行 typedef:
typedef struct S_LIGNE LIGNE;
struct S_LIGNE {
LIGNE *precedent;
PERSONNE individu;
LIGNE *suivant;
};
This way, your compiler knoww that LIGNE
is a typedef for struct S_LIGNE
.这样,您的编译器就知道
LIGNE
是struct S_LIGNE
的 typedef。
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