使用正则表达式替换 substring 但保留空格

Question

I am replacing content in a string with a predetermined character based on if the substring is wrapped in quotes.

const string = "The \"quick\" brown \"fox\" 'jumps' over the 'lazy dog'";
const pattern = /(?:'([^']*)')|(?:"([^"]*)")/g;
const redactedText = string.replace(pattern, (str) => {
  const strippedString = str.replace(/['"]+/g, '');
  return 'x'.repeat(strippedString.length);
}

Output: The xxxxx brown xxx xxxxx over the xxxxxxxx

However I was to preserve the space within lazy dog

So it would output: The xxxxx brown xxx xxxxx over the xxxx xxx

What am I missing to do this?

Answer 1

You can use another replace for non space characters instead of "x".repeat

 const string = "The \"quick\" brown \"fox\" 'jumps' over the 'lazy dog'"; const pattern = /(?:'([^']*)')|(?:"([^"]*)")/g; const redactedText = string.replace(pattern, (str) => { const strippedString = str.replace(/['"]+/g, ''); return strippedString.replace(/[^\ ]/g,'x'); // replace non space character w/"x" }) console.log(redactedText)