运算符等于重载 c++ 显然不起作用

Question

Can someone explain me why the cout doesn't get called here?

#include <iostream>

using namespace std;

class Test {
public:
    int a = 1;

    Test &operator=(const Test &other) {
        cout << "overloading here" << endl;
        return *this;
    }
};


int main() {
    Test t1;
    Test &t3 = t1;
    return 0;
}

Answer 1

    Test &t3 = t1;

is creating a reference for Test and initiaizing that. = operator is not used there. There are no cout other than inside operator= , so cout won't be called.

Note that

    Test t3 = t1;

(without & ) will also not call operator= because this is an initialization of object and a constructor is used for that.

To use operator= , you should do like

    Test t3;
    t3 = t1;