Bash 计算使用 uniq 数组

Question

arrays are driving my crazy on Linux. I two arrrays called x, y. Those arrays contain one IP that repeats a crazy amount of times.

x=(182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59 182.100.67.59)

y=(218.52.41.22 218.52.41.22 218.52.41.22 218.52.41.22 218.52.41.22 218.52.41.22 
218.52.41.22 218.52.41.22 218.52.41.22 218.52.41.22 218.52.41.22 218.52.41.22 
218.52.41.22 218.52.41.22 218.52.41.22 218.52.41.22 218.52.41.22 218.52.41.22 
218.52.41.22 218.52.41.22 218.52.41.22 218.52.41.22 218.52.41.22)

How can I count variables x, and y. Using something like uniq.

(IFS=""; sort <<< "$x") | uniq -c

But it does not work

EDIT 1:

Desired Output:

6 182.100.67.59

24 218.52.41.22

EDIT 2:

I have implemented this simple for:

for i in $x; do
            
            echo $i | uniq -c
            
            done

It prints out

      1 182.100.67.59
      1 182.100.67.59
      1 182.100.67.59
      1 182.100.67.59
      1 182.100.67.59
      1 182.100.67.59
      1 182.100.67.59
      1 182.100.67.59
      1 182.100.67.59
      1 182.100.67.59
      1 182.100.67.59
      1 182.100.67.59
      1 182.100.67.59
      1 182.100.67.59
      1 182.100.67.59

But the desired output would be:

15 182.100.67.59

Answer 1

First print the array values on lines.
Then sort.
Then uniq.

printf "%s\n" "${x[@]}" "${y[@]}" | sort | uniq -c

Answer 2

Your code is just printing first value. To read the whole array just add $x[*]

(IFS=""; sort <<< "$x[*]") | uniq -c