如何使用 Python Turtle 实现碰撞检测

Question

Good afternoon I need my program to reset when my python turtle hits a circle. There are 53 circles. Here is the turtle.

move = turtle.Turtle()
move.penup()
showturtle()
turtle.hideturtle()
move.setposition(-500,0)
move.pencolor('cyan')
move.fillcolor("blue")
move.pos()
move.speed()
move.shapesize(3,3,3)



turtle.fillcolor("blue")
turtle.shapesize(3,3,3)
outline = ['white', 'green', 'red', 'blue', 'purple', 'yellow', 'orange','black','gray']
colors = ['red', 'blue', 'green', 'purple', 'yellow', 'orange', 'black','gray']
size = ['4,4,4', '2,2,2']
bg = ['blue', 'green', 'purple', 'yellow', 'orange', 'black', 'gray']
def up():
   move.forward(25)

def down():
   move.backward(15)

def left():
    move.left(30)


def right():
    move.right(30)

def b():
   turtle.bgcolor(random.choice(bg))


 


def clickleft(x,y):
    move.fillcolor(random.choice(colors))

def clickright(x,y):
    move.pencolor(random.choice(outline))


    
turtle.listen()

turtle.onscreenclick(clickleft, 1)
turtle.onscreenclick(clickright, 3)

turtle.onkey(up, 'Up')
turtle.onkey(down, 'Down')
turtle.onkey(left, 'Left')
turtle.onkey(right, 'Right')
turtle.onkey(b, 'b')

And here is the code for all the asteroids. They have to be this size and shape unless there's another way to make sure the circles can't overlap

WIDTH, HEIGHT = 400, 400
ASTEROID_RADIUS = 53
NUMBER_ASTEROIDS = 53
CURSOR_SIZE = 20


asteroid = Turtle()

if move.distance(asteroid)<5:
    move.goto(0,0)

asteroid_prototype = Turtle()
asteroid_prototype.hideturtle()
asteroid_prototype.color('grey')
asteroid_prototype.shape('circle')
asteroid_prototype.shapesize(ASTEROID_RADIUS / CURSOR_SIZE)
asteroid_prototype.speed('fastest')  # because 15 isn't a valid argument
asteroid_prototype.penup()

asteroids = []

for _ in range(NUMBER_ASTEROIDS):
    asteroid = asteroid_prototype.clone()
    asteroid.setposition( \
        randint(ASTEROID_RADIUS - WIDTH, WIDTH - ASTEROID_RADIUS), \
        randint(ASTEROID_RADIUS - HEIGHT, HEIGHT - ASTEROID_RADIUS) \
    )

    while any(map((lambda a: lambda b: a.distance(b) < ASTEROID_RADIUS)(asteroid), asteroids)):
        asteroid.setposition( \
            randint(ASTEROID_RADIUS - WIDTH, WIDTH - ASTEROID_RADIUS), \
            randint(ASTEROID_RADIUS - HEIGHT, HEIGHT - ASTEROID_RADIUS) \
         )
   

    asteroid.showturtle()
    asteroids.append(asteroid)

The code has to be like this so the circles don't overlap Thank you in advance

Answer 1

1. Define a function that will reset the player's position and the positions of all the asteroids.

2. Add a while loop to constantly check to see if the player collides with any of the asteroids.

3. When detected a collision, call the reset function.

def reset(asteroids):
    move.setposition(-500,0)
    for asteroid in asteroids:
        asteroid.goto(1000, 1000)
    asteroids2 = []
    for asteroid in asteroids:
        asteroid.setposition( \
            randint(ASTEROID_RADIUS - WIDTH, WIDTH - ASTEROID_RADIUS), \
            randint(ASTEROID_RADIUS - HEIGHT, HEIGHT - ASTEROID_RADIUS) \
        )

        while any(map((lambda a: lambda b: a.distance(b) < ASTEROID_RADIUS)(asteroid), asteroids2)):
            asteroid.setposition( \
                randint(ASTEROID_RADIUS - WIDTH, WIDTH - ASTEROID_RADIUS), \
                randint(ASTEROID_RADIUS - HEIGHT, HEIGHT - ASTEROID_RADIUS) \
             )
       
        asteroid.showturtle()
        asteroids2.append(asteroid)
    return asteroids2

turtle.listen()

turtle.onscreenclick(clickleft, 1)
turtle.onscreenclick(clickright, 3)

turtle.onkey(up, 'Up')
turtle.onkey(down, 'Down')
turtle.onkey(left, 'Left')
turtle.onkey(right, 'Right')
turtle.onkey(b, 'b')
while True:
    if any(move.distance(asteroid) < 37 for asteroid in asteroids):
        asteroids = reset(asteroids)
    update()