Python 使用文件字节访问 zip 文件并遍历每个文件以将它们保存到数据帧中返回找不到文件的错误

Question

I am calling an API which will result in a zip file that might contain multiple CSV files:

import zipfile
from io import BytesIO

api_url = res.json()['export_url']
new_res = requests.get(api_url, auth=(user, pass))
filebytes = BytesIO(new_res.content)
myzipfile = zipfile.ZipFile(filebytes)
a = myzipfile.extractall
for name in myzipfile.namelist():
    print(name)

I can clearly see the file names but can't read them into data frame each one of them:

for name in myzipfile.namelist():
    df = pd.read_csv(name)

The error is:

FileNotFoundError: [Errno 2] File data.csv does not exist: 'data.csv'

I tried:

for name in myzipfile.printdir():
    print(name)

and read as csv but didn't work.

Answer 1

The file is still zipped - you cannot just read the contained file as you would normally. Zipfile has its own open function for reading contained files. You can then read the data into a dataframe with pandas.

for name in myzipfile.namelist():
    with myzipfile.open(name) as myfile:
        df = pd.read_csv(myfile)