如何使用 javascript 删除 firebase 实时数据库的子节点

Question

firebase child node generated by push key

Using Javascript, how do I delete a child node generated by push key on firebase realtime database

 function createpin() {
  var pin = document.getElementById("createpin").value;
  var firebaseRef = firebase.database().ref();
  let data = {
    Pin: pin,
  }

  firebaseRef.child("Pins/").push(data);

the code above is used to add data to the realtime database

Answer 1

firebase.database().ref("Path Of Child Node").remove();

first you need to get the exact path which you want to remove.

Answer 2

Step 1: Import a firebase file configuration

import firebase from "../firebase";

Step2 : Specify the exact path you want to remove

const db = firebase.ref("Name Table you want to inject");

Step3: Create a method to remove firebase data in Real-Time Database

// delete all items
const remove = () => {
  return db.remove();
};

// delete a child node
const remove = (key) => {
  return db.child(key).remove();
};

Step 4: Import and use the method into necessary component you need to remove the element

const removeAll = () => {
   NameService.remove().then(() => {})
                       .catch(e => console.log(e))
 }

<button onClick={removeAll}> Remove All </button>