Select 唯一的 field1 有 >1 个不同的 field2 实例与之关联？

Question

How can I query for the distinct field1 instances that have multiple distinct corresponding field2 values?

field1	field2
a	apple
b	grape
c	banana
b	orange
a	apple

In this example I want to return "b", since there are at least 2 distinct values (grape and orange) for field2 that correspond to it. I don't wan't "a" since there is only 1 unique field2 value that corresponds, "apple".

I have tried

with all_unique_combos as (
select distinct field1, field2
from table
)

select field1
from all_unique_combos
group by field1
having count(field2) > 1

I actually think this is right and would give me what I need. But at the moment it's returning 0 rows so I kinda need a sanity check. Thanks for any input either way.

Answer 1

You can use aggregation:

select field1
from t
group by field1
having min(field2) <> max(field2);

Answer 2

A straight-forward approach uses group by and having :

select field1
from mytable
group by field1
having min(field2) <> max(field2)

Answer 3

Using COUNT(DISTINCT...) :

select field1
from tab
group by field1
having count(disitnct field2) > 1