当真正的循环不起作用时在里面增加

Question

x=0

def add(var):

    var+=1
    return var

while True:

    y = add(x)
    print(y)

This code gives output only as 1 for every iteration. But I need this code to increment the value, with the same code(architecture).

Answer 1

you can try this code

i = 1
def add(var):
    var+=1
    return var
    
while True:
  print(i)
  i = add(i)

Answer 2

You may try this...

x=0 
def add(var): 
    var+=1 
    return var 
while True: 
    x = add(x) 
    print(x)

Answer 3

Try this

def add(var):
    var+=1
    return var
x = 0
while True:
    y = add(x)
    print(x)

You can define y outside the loop, then add it to y

Or just do this:

y = 0
while True:
    print(y)
    y += 1

You can use a for-loop instead too.

for i in range(100): # whatever number you want to loop.
    print(i)

Answer 4

You keep passing x = 0, so it will always print 1. Try replacing x with y instead.