[英]how can I use pandas dataframe with out of bounds datetime?
I have a dataframe like this:我有一个像这样的 dataframe:
housing_deals.head()
Out[2]:
price sale_date
0 477,000,000 1396/10/30
1 608,700,000 1396/11/25
2 580,000,000 1396/10/03
3 350,000,000 1396/12/05
4 328,000,000 1396/03/18
how can I convert sale_date column to pandas datetime如何将 sale_date 列转换为 pandas 日期时间
i see below我在下面看到
How to work around Python Pandas DataFrame's "Out of bounds nanosecond timestamp" error? 如何解决 Python Pandas DataFrame 的“越界纳秒时间戳”错误?
but yet i cannot do that for my dataframe但我不能为我的 dataframe 做到这一点
You can convert values to daily periods, check docs :您可以将值转换为每日周期,查看文档:
df['sale_date'] = df['sale_date'].apply(lambda x: pd.Period(x, freq='D'))
print (df)
price sale_date
0 477,000,000 1396-10-30
1 608,700,000 1396-11-25
2 580,000,000 1396-10-03
3 350,000,000 1396-12-05
4 328,000,000 1396-03-18
EDIT: You can convert values to numbers and then use function with docs :编辑:您可以将值转换为数字,然后将 function 与docs一起使用:
print (df['sale_date'].str.replace('/','').astype(int))
0 13961030
1 13961125
2 13961003
3 13961205
4 13960318
Name: sale_date, dtype: int32
def conv(x):
return pd.Period(year=x // 10000,
month=x // 100 % 100,
day=x % 100, freq='D')
df['sale_date'] = df['sale_date'].str.replace('/','').astype(int).apply(conv)
print (df)
price sale_date
0 477,000,000 1396-10-30
1 608,700,000 1396-11-25
2 580,000,000 1396-10-03
3 350,000,000 1396-12-05
4 328,000,000 1396-03-18
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