React-native 询问 iOS 启用 wifi

Question

I don't find a way to check if wifi is enabled on iOS. I am currently creating tracking app and to increase user location we need wifi enabled. So I want to ask user to enable wifi, but I want to check if it's currently enabled or not. Is there a way?

Answer 1

With https://github.com/react-native-netinfo/react-native-netinfo you can check it by:

NetInfo.fetch().then(state => {
  console.log("Connection type", state.type);
  console.log("Is connected?", state.isConnected);
});

Answer 2

You can use this code to check connection type:-

 NetInfo.fetch().then(state => {
  this.setState({
    connType: state.type
  })
 });

If connection type is wifi then ok if not you can display some popup to enable wifi.

You can use the following code to open settings, so user can easily enable their wifi

  openWiFi = () => {
    if (Platform.OS === "ios") {
        Linking.openURL('app-settings:')
    }else{
        // import DeviceSettings from 'react-native-device-settings';
        DeviceSettings.wifi();
    }
   }

Answer 3

You can get desired status by below method. Write this method in native & access from React Native by using promise. Refer: https://francescocrema.it/check-wifi-status-on-ios-in-swift/

func isWiFiOn() -> Bool {
        var address : String?
        var ifaddr : UnsafeMutablePointer<ifaddrs> = nil
        if getifaddrs(&ifaddr) == 0 {
            var ptr = ifaddr
            while ptr != nil {
                defer { ptr = ptr.memory.ifa_next }
                let interface = ptr.memory
                let addrFamily = interface.ifa_addr.memory.sa_family
                if addrFamily == UInt8(AF_INET) || addrFamily == UInt8(AF_INET6) {
                    if let name = String.fromCString(interface.ifa_name) where name == "awdl0" {
                        if((Int32(interface.ifa_flags) & IFF_UP) == IFF_UP) {
                            return(true)
                        }
                        else {
                            return(false)
                        }
                    }
                }
            }
            freeifaddrs(ifaddr)
        }
        return (false)
    }