正则表达式在最后一次出现字符后查找文本直到另一个字符

Question

I am looking to find a regular expression to extract information starting with " including: " and ending with the text after the last occurence of the character "\n*" or "\n•" until the character "\n". In other words, i am trying to find an ending as the first occurence of "\n" right after the last occurence of "\n*" or "\n•". I have tried this demo but doesn't work as i want it to. I would like to include the next sentence untill "guidance.\n". I am using python and i am trying to extract that to a new column in my pandas DataFrame called "Skills". The "Job Description" column has the information

df["Skills"]=df["Job description"].str.extract("including:((?:.)*\\n[*|•])")

Answer 1

You might use

(?s)\bincluding:(.*\\n[*•]).*?\\n(?![*•])

• (?s) Inline modifier to make the dot match a newline
• \bincluding: Match including: preceded by a word boundary
• ( Capture group 1
  • .*\\n[*•] Match till the last occurrence of \n followed by either * or •
• ( Close group 1
• .*?\\n Match till the first occurrence of \n

Regex demo

Or when \\n is a real newline

(?s)\bincluding:(.*\n[*•]).*?\n(?![*•])

Regex demo

For example

df["Skills"] = df["Job description"].str.extract(r"(?s)\bincluding:(.*\n[*•]).*?\n(?![*•])")