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使用字符串向量时 C++ 中的分段错误

[英]Segmentation Fault in C++ while using string vectors

My code is for an online coding practice site, I have been doing many of the challenges but I cannot seem to get around the segmentation fault error on this one.我的代码是用于在线编码练习网站的,我一直在做很多挑战,但我似乎无法解决这个问题上的分段错误错误。

The aim of the code is to find the longest length strings in a string vector (up to 10 strings long) and then to return a string vector containing just those longest strings in order.代码的目的是在字符串向量中找到最长的字符串(最多 10 个字符串),然后按顺序返回仅包含最长字符串的字符串向量。

I believe logically my code works, but I can't test it.我相信我的代码在逻辑上是有效的,但我无法测试它。 I am still new to vectors so can't seem to properly understand other answers on here in relation to my issue.我对向量还是新手,所以似乎无法正确理解这里与我的问题有关的其他答案。

vector<string> allLongestStrings(vector<string> inputArray) {

    vector<string> longestStrings;            // vector
    int longest_size = longestStrings.size(); // int
    int longestArrayCounter = 0;              // int. For filling longestStrings whenever 
                                              //  there is a long string
    int longest_string = 0;                   // int. For recording the size of the longest string

    for (int i = 0; i < inputArray.size(); i++) {  
        // Loop will:  
        //1. Measure size of string in input array 
        //2. if longest will change value of longest_string and clear longestStrings
        //3. If the same length as longest_string will add it to longestStrings vector
        //4. if it is shorter it will be ignored
       if (inputArray[i].size() > longest_string) { // input vector
          longest_string = inputArray[i].size();     // vector

       longestStrings.clear(); //clearing the vector to only store longest string values
       longestArrayCounter = 0; //reset counter for longestStrings
       longestStrings[longestArrayCounter++] = inputArray[i];//puts new longest string from input into my vector
       }

       if (inputArray[i].size() == longest_string) { 
       longestStrings[longestArrayCounter++] =inputArray[i];// my vector and input vector
       }
   }
   return longestStrings;
}

       longestStrings.clear();
       longestArrayCounter = 0;
       longestStrings[longestArrayCounter++] = inputArray[i];

is bad because you are doing assignment to non-existent element.不好,因为您正在对不存在的元素进行分配。

Instead of the two而不是这两个

longestStrings[longestArrayCounter++] = inputArray[i];

you should do你应该做

longestStrings.push_back(inputArray[i]);

Then, std::vector will manage the size for you, so you don't have to manage longestArrayCounter by yourself.然后, std::vector将为您管理大小,因此您不必自己管理longestArrayCounter Use longestStrings.size() to obtain the size.使用longestStrings.size()获取大小。

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