自动从 azure 存储解压缩受密码保护的 Zip 文件？

Question

I'm just wondering is there a way to extract a password protected zip file from Azure Storage. I tried using a python Azure Function to no avail but had a problem reading the location of the file.

Would the file have to stored on a shared location temporarily in order to achieve?

Just looking for a bit of direction here am I missing a step maybe?

Regards, James

Answer 1

Azure blob storage provides storing functionality only, there is no running env to perform unzip operation. So basically, we should download.zip file to Azure function, unzip it and upload files in.zip file 1 by 1.

For a quick test, I write an HTTP trigger Azure function demo that unzipping a zip file with password-protected, it works for me on local:

import azure.functions as func
import uuid
import os
import shutil
from azure.storage.blob import ContainerClient
from zipfile import ZipFile

storageAccountConnstr = '<storage account conn str>'
container = '<container name>'

#define local temp path, on Azure, the path is recommanded under /home 
tempPathRoot = 'd:/temp/'
unZipTempPathRoot = 'd:/unZipTemp/'


def main(req=func.HttpRequest) -> func.HttpResponse:
    reqBody = req.get_json()
    fileName = reqBody['fileName']
    zipPass =  reqBody['password']

    container_client = ContainerClient.from_connection_string(storageAccountConnstr,container)

    #download zip file 
    zipFilePath = tempPathRoot + fileName
    with open(zipFilePath, "wb") as my_blob:
       download_stream = container_client.get_blob_client(fileName).download_blob()
       my_blob.write(download_stream.readall())

    #unzip to temp folder
    unZipTempPath = unZipTempPathRoot + str(uuid.uuid4())
    with ZipFile(zipFilePath) as zf:
        zf.extractall(path=unZipTempPath,pwd=bytes(zipPass,'utf8'))

    #upload all files in temp folder
    for root, dirs, files in os.walk(unZipTempPath):
        for file in files: 
            filePath = os.path.join(root, file)
            destBlobClient = container_client.get_blob_client(fileName + filePath.replace(unZipTempPath,''))
            with open(filePath, "rb") as data:
                destBlobClient.upload_blob(data,overwrite=True)
    
    #remove all temp files 
    shutil.rmtree(unZipTempPath)
    os.remove(zipFilePath)

    return func.HttpResponse("done")

Files in my container:

Result:

Using blob triggers will be better to do this as it will cause time-out errors if the size of your zip file is huge.

Anyway, this is only a demo that shows you how to do this.