检查 bash 中的条件并运行命令

Question

I am need of running series of commands after checking the conditions. I tried this

#var1 results in output active or inactive
var1= systemctl is-active docker


#Function for enabling and running the docker service

function run {
echo "Starting Docker service.."
sudo systemctl enable docker
sudo systemctl start docker
mkdir /mnt/new/hello_test
}

# Checking whether the docker service is up or not

if [[ $var1 -eq inactive ]]
        then
        echo "$(run)"
else
        echo "Docker service is  running..." ; touch /mnt/new/testingg;
fi

In this script, it is only checking 1st condition. ANy help would be appreciated. Thanks!

Answer 1

In this script, it is only checking 1st condition

Because -eq is for numbers. Both sides [[ <this> -eq <that> ]] are converted to numbers. Because they are not numbers but strings active and inactive , they are interpreted as variable names and because these variables are not defined, both sides are equal zero.

But forget it, just execute the actual command in if :

run() {
   echo "Starting Docker service.."
   sudo systemctl enable docker
   sudo systemctl start docker
   mkdir /mnt/new/hello_test
}

if ! systemctl is-active -q docker; then
        run
else
        echo "Docker service is  running..."
        touch /mnt/new/testingg;
fi

Anyway to compare strings, use = :

[[ "stringone" = "stringsecond" ]]
# like:
var1=$(systemctl is-active docker)
[[ "$var1" = "inactive" ]]