尝试根据 Google Apps 脚本中的关键字设置背景颜色

Question

I'm trying to highlight a row in a table based off of the relevant keyword. However, my attempts at setting the background color of my range of cells have not yielded any colors. I used loggers inside the if/else statement and they all worked, so I think I'm doing setBackgroundColor wrong somehow.

function statusHighlighter(){
  
  var ss = SpreadsheetApp.getActiveSpreadsheet();
  var sheetName = ss.getActiveSheet();
  var sheetValues = ss.getDataRange().getValues();

  sheetValues.forEach(function(row, index) {
    var acctStatus = row[7];
    var highlightRange = sheetName.getRange(index+1, 1, 1, sheetName.getLastColumn());

    if(acctStatus === "Kept"){
      highlightRange.setBackgroundColor('##fffec4');
      Logger.log(acctStatus + " " + index);
    } else if(acctStatus === "Suspended"){
      highlightRange.setBackground('##cf4a4a');
    } else if(acctStatus === "Deleted"){
      highlightRange.setBackground('##6c75ad');
    }
  });
} 

Answer 1

Explanation / Issues:

There is one issue in your code and a couple of optimizations that I would like to suggest.

• The hex color codes must contain only one # but you are using two ## .

• You are iteratively using setBackground but instead you can create an array with colors inside the forEach loop and then use setBackgrounds to set the colors in one go. Have a look at best practices to see why.

• Since you have a particular column of interest, it makes sense to consider only one column instead of the full dataRange . In the following script, acctStatusVals considers only column 8 . I choose 8 because in your code you use the array index for 7 which is equivalent for column 8 . Be careful on that. In my code, 8 means column H . Adjust this to your needs. To convert the 2D array into 1D since we are using a single column, you can use flat .

• I use the following expression: Array(lastCol).fill('#6c75ad') to create an array of lastCol number of elements ( last column with content ) and fill it with the same value, because the goal is to color the full row with the same color value.

Optimized Solution:

Be careful with the active sheet. Make sure you select the right sheet before you run this code. I would advice you to use ss.getSheetByName('Sheet1'); but I leave it as a comment since this step is optional.

function statusHighlighter(){ 
  const ss = SpreadsheetApp.getActiveSpreadsheet();
  const sheetName = ss.getActiveSheet();
//  const sheetName = ss.getSheetByName('Sheet1'); // change to the name of your sheet
  const lastRow = sheetName.getLastRow();
  const lastCol = sheetName.getLastColumn();
  const acctStatusVals = sheetName.getRange(1,8,lastRow).getValues().flat();
  const colors = [];
  acctStatusVals.forEach(acctStatus=>{
   if(acctStatus === "Kept"){
      colors.push(Array(lastCol).fill('#fffec4'));
    } else if(acctStatus === "Suspended"){
      colors.push(Array(lastCol).fill('#cf4a4a'));
    } else if(acctStatus === "Deleted"){
      colors.push(Array(lastCol).fill('#6c75ad'));
    }                   
  });
  sheetName.getRange(1, 1, lastRow, lastCol).setBackgrounds(colors);
}

Sheet used for the above script: