[英]Sort elements of secondary diagonal in ascending order C++
As I think, I need to transform function printSecondaryDiagonal
(that actually print elements of secondary diagonal) into one-dimensional array and then sort its elements in ascending order, right?正如我所想,我需要将 function printSecondaryDiagonal
(实际上打印辅助对角线的元素)转换为一维数组,然后按升序对其元素进行排序,对吗?
PS Two-dimensional array in the beginning must be necessarily a dynamic one. PS 一开始的二维数组一定是动态的。 Also, cannot do it using vector
.此外,不能使用vector
来做到这一点。 Only malloc
, calloc
and new
只有malloc
, calloc
和new
#include <iostream>
#include <iomanip>
using namespace std;
void getManual(int** arr, int rows, int columns);
void getRandom(int** arr, int rows, int columns);
void printSecondaryDiagonal(int** arr, int rows, int columns);
void main() {
int rowCount = 5;
int colCount = 6;
cout << "Enter quantity of rows: ";
cin >> rowCount;
cout << "Enter quantity of columns: ";
cin >> colCount;
int** arr = new int* [rowCount];
for (int i = 0; i < rowCount; i++) {
arr[i] = new int[colCount];
}
cout << " Array formation algorithm\n";
start:
cout << "Input number : \n1 for manual\n2 for random\n";
int k;
cin >> k;
switch (k) {
case 1: getManual(arr, rowCount, colCount);
break;
case 2: getRandom(arr, rowCount, colCount);
break;
default:cout << "Input 1 or 2, please.";
cout << endl << endl;
goto start;
}
cout << endl;
printSecondaryDiagonal(arr, rowCount, colCount);
for (int i = 0; i < rowCount; i++) { //очищуємо память для кожного рядка
delete[] arr[i];
}
delete[] arr;
}
void getManual(int** arr, int rows, int columns) { //введення з клавіатури
for (int i = 0; i < rows; i++) {
for (int j = 0; j < columns; j++) {
cout << "a[" << i << "][" << j << "]=";
cin >> arr[i][j];
//cin >> *(*(arr + i) + j); //вказівникова форма
}
}
}
void getRandom(int** arr, int rows, int columns) { //випадкова генерація чисел
int lowest = -21, highest = 34;
int i, j;
srand(time(NULL));
// ініціалізація масива
for (i = 0; i < rows; i++) {
for (j = 0; j < columns; j++) {
arr[i][j] = lowest + rand() % (highest - lowest + 1);
cout << setw(7) << arr[i][j];
}
cout << endl;
}
}
Function that I need to transform into one-dimensional array and which is the main problem for me: Function 我需要转换为一维数组,这对我来说是主要问题:
void printSecondaryDiagonal(int** arr, int rows, int columns) {
cout << "Secondary Diagonal: ";
for (int i = 0; i < rows; i++) {
for (int j = 0; j < columns; j++) {
// Condition for secondary diagonal
if ((i + j) == (columns - 1)) {
cout << arr[i][j] << setw(7);
}
}
}
}
The elements of the secondary diagonal can be extract with one for loop as I will show.正如我将展示的那样,可以使用一个 for 循环提取次对角线的元素。 The secondary diagonal will be save in an 1-d array `secDiag[i]`.次对角线将保存在一维数组 `secDiag[i]` 中。 Then, using `std::sort` in `algorithm` head file to sort this array in ascending order.然后,使用 `algorithm` 头文件中的 `std::sort` 对这个数组进行升序排序。
void printSecondaryDiagonal(int** arr, int rows, int columns) {
cout << "Secondary Diagonal: ";
int *secDiag = new int [rows];
int r, c;
for (r = 0; r < rows ; r++) {
c = columns - r -1;
if (c < 0) break;
secDiag[r] = arr[r][c];
}
for (int i =0; i<r; i++) std::cout << setw(7) << secDiag[i];
std::cout << std::endl;
std::cout << "After sorted: ";
std::sort(secDiag, secDiag+r);
for (int i =0; i<r; i++) std::cout << setw(7) << secDiag[i];
std::cout << std::endl;
delete [] secDiag;
}
A test run:试运行:
Enter quantity of rows: 3
Enter quantity of columns: 3
Array formation algorithm
Input number :
1 for manual
2 for random
2
33 -13 29
-7 -2 10
-8 18 6
Secondary Diagonal: 29 -2 -8
After sorted: -8 -2 29
void printSecondaryDiagonal(int** arr, int rows, int columns) {
cout << "Secondary Diagonal: ";
int i = 0;
int j = columns - 1;
int k = 0;
int size =0;
if (rows>columns)
{
size = columns;
}
else
{
size = rows;
}
int *diagonal = new int[size];
while (i < rows && j >= 0)
{
diagonal[k] = arr[i][j];
cout << arr[i][j] << setw (7);
i++;
j--;
k++;
}
for (int i = 0; i < size - 1; i++)
{
for (int j = 0; j < size - i - 1; j++)
{
if (diagonal[j] > diagonal[j + 1])
{
// swap arr[j+1] and arr[j]
int temp = diagonal[j];
diagonal[j] = diagonal[j + 1];
diagonal[j + 1] = temp;
}
}
}
for (int r = 0; r < size; r++)
{
cout << diagonal[r] << endl;
}
delete [] diagonal;
}
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