[英]strsep() causes segfault - why?
I am a little bit confused about pointer-of-pointer-const-var-string-char;) Her's my code:我对pointer-of-pointer-const-var-string-char有点困惑;)她是我的代码:
char* str_get_var(char *string,char delim)
{
char *found,
*found2,
*teststring;
printf("var string: %s\t",string);
teststring=strdup(string);
printf(" ---- var teststring: %s\n",teststring);
string=strdup(teststring);
found = strsep(&teststring,&delim);
printf("teststring \t var found: %s\n",found);
found2 = strsep(&string,&delim);
printf("string \t\t var found2: %s\n",found2);
return found;
}
int main(int argc, char *argv[])
{
char *message;
char trenner;
char *gefun;
message="ehzg=1";
trenner = '=';
printf("Start\n");
gefun=str_get_var(message,trenner);
printf("Ende\n");
return(0);
}
The programm produces the following output:该程序产生以下 output:
Start
var string: ehzg=1 ---- var teststring: ehzg=1
teststring var found: ehzg
string var found2: ehzg
Ende
As you might see from the code I would say the strdup
to teststring is not needed as I would expect I can use the *string
directly.正如您从代码中看到的那样,我会说不需要到 teststring 的strdup
,因为我希望我可以直接使用*string
。 However, as soon as I comment the following line I am getting a SegFault:但是,只要我评论以下行,我就会收到 SegFault:
\\string=strdup(teststring);
Her's the output when commented out:注释掉时,她是 output:
Start
var string: ehzg=1 ---- var teststring: ehzg=1
teststring var found: ehzg
Speicherzugriffsfehler
So my question(s): How can I use *string
directly for strsep?所以我的问题是:如何直接将*string
用于 strsep? Why do I get a segfault when not doing strdup
with the same content?为什么不使用相同内容执行strdup
时会出现段错误?
(BTW: Coding on Raspbian, if important). (顺便说一句:在 Raspbian 上编码,如果重要的话)。
Thanks!谢谢! /knebb /knebb
strchr
could be used to find an =
in the literal string. strchr
可用于在文字字符串中查找=
。
#include <stdio.h>
#include <string.h>
char* str_get_var(char *string,char delim)
{
char *found2 = NULL;
printf("var string: %s\t",string);
found2 = strchr ( string, delim);
if ( NULL != found2) {
printf ( "string \t\t var found2: %s\n", found2);
}
return found2;
}
int main(int argc, char *argv[])
{
char *message = "ehzg=1";
char trenner = '=';
char *gefun = NULL;
printf ( "Start\n");
gefun = str_get_var ( message, trenner);
printf ( "Ende\n");
if ( NULL != gefun) {
printf ( "%.*s\n", (int)( gefun - message), message);
printf ( "%s\n", gefun);
}
return(0);
}
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