从 spring 启动应用程序调用 exe 文件

Question

I have somefile.exe in my local and i am currently invoking this exe using process builder by giving absolute path like below

ProcessBuilder builder = new ProcessBuilder();
builder.command("C:\\path\\to\\the\\somefile.exe","other commands");

I am using spring boot and i dont want to hardcode the absolute path to local, instead i want to make the exe available in project folder.

Where should i put the exe in project folder? I tried placing the exe file in resources folder but does not work.

Answer 1

put the exe file in src/main/resources folder. then you can access it from root of the class path. see this guide for accessing files in your classpath.