编译时出错：不兼容的类型和类似的警告（附图）

Question

I'm writing a function that returns the inverse of an array using recursivity but I keep getting these warnings:

Here is my code

#include <stdio.h>
#include <stdlib.h>

int inv( float* t[],int n)
{   float u;
    if (n==0) return 0;
    else
    {
        u=*t;
        *t=*(t+n);
        *(t+n)=u;
        return(inv(*(t+1),n-1));
    }

}

int main()
{
    float t[]={1,2,3,4,5,6,7,8,9};
    int n=sizeof t /sizeof *t;
    int i=0;
    inv(t,n);
    for(i=0;i<n;i++)printf("%f",t[i]);
    return 0;
}

Answer 1

int inv( float* t[],int n)

Here, float* t[] declares an array of pointers. Please note that *t[i] = *(*(t+i))

For i = 0, *(*(t+i)) = *(*(t)) = *(*t) .

Here, *t is of type float* , and u is of type float.

Using the expression u=*t; gives you that error (assigning float* value to float )

Solution: Change int inv( float* t[],int n) to int inv( float t[],int n)

Answer 2

I use a procedure to arrange the array elements in descending order

#include <stdio.h>
#include <stdlib.h>

void revs(int i, int n, float *arr)
{
   if(i==n)
  {
     return ;
  }
  else
  {
       revs(i+1, n, arr);
       printf("%.f ", arr[i]);
  }
   return 0;
}

int main()
{
    float t[]={1,2,3,4,5,6,7,8,9};
    int n=sizeof t /sizeof t[0];
    int i=0;
    revs(0,n,t);
}

Answer 3

It looks like the intended action of OP's function inv is to reverse the elements of an array of n float values in place, using recursion.

In the original inv code, the parameter declaration float* t[] will be adjusted to be equivalent to float** t by the compiler. This needs to be changed to float t[] or equivalently float* t .

In the original inv code, the return value is either 0 or the result of the recursive call to itself, which can only be 0 . Therefore the return value is of no use. It would be better to change the return type of the function to void .

In the inv function, the parameter n is set to the length of the array in the initial call from main . The function swaps the values of elements at indices 0 and n before recursing, but there is no element at index n . The last element has index n-1 . The function should swap the elements at indices 0 and n-1 before recursing. After swapping the first and last elements, the remaining n-2 elements with indices from 1 to n-2 can be swapped by a recursive call. The original inv code uses the value n-1 in the recursive call, but it should be n-2 .

If n is less than 2, the inv function does not need to do anything.

A possible implementation of inv based on OP's original code follows:

void inv(float* t,int n)
{   
    float u;
    if (n>=2)
    {
        u=*t;
        *t=*(t+n-1);
        *(t+n-1)=u;
        inv(t+1,n-2));
    }
}

The same function can be written using array subscripting operators as follows:

void inv(float t[],int n)
{   
    float u;
    if (n>=2)
    {
        u=t[0];
        t[0]=t[n-1];
        t[n-1]=u;
        inv(&t[1],n-2));
    }
}