[英]Android start Activity 2 but rest at MainActivity
I have MainActivity which has got a button that opens Activity 2. Everything from Activity 2 should be calculated and be run but the user should rest at MainActivity?我有 MainActivity,它有一个打开 Activity 2 的按钮。应该计算并运行 Activity 2 中的所有内容,但用户应该在 MainActivity 中使用 rest? How do I do this?
我该怎么做呢?
I found a solution where I dont run the "setContentView()" but then my app crashes.我找到了一个解决方案,我不运行“setContentView()”但随后我的应用程序崩溃了。
You want to change the view of application but does not want the user to change activity.您想更改应用程序的视图但不希望用户更改活动。
Use two different layout in xml file with id:在具有 id 的 xml 文件中使用两种不同的布局:
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent">
<LinearLayout
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:orientation="vertical"
android:id="@+id/first_view">
<Button
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="Button1"
android:id="@+id/button"
android:background="#358a32" />
</LinearLayout>
<LinearLayout
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:orientation="vertical"
android:id="@+id/second_view"
android:visibility="gone">
</LinearLayout>
<LinearLayout>
Then onclick of button:然后按钮的onclick:
public class MainActivity extends Activity {
boolean firstViewOff = false;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
Button button = (Button) findViewById(R.id.button1);
LinearLayout first_view = (LinearLayout) findViewById(R.id.first_view);
LinearLayout second_view = (LinearLayout) findViewById(R.id.second_view);
button.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
firstViewOff = true;
first_view.setVisibility(View.GONE);
second_view.setVisibility(View.VISIBLE);
}
});
}
@override
public void onBackPressed(){
super.onBackPressed();
if(firstViewOff){
second_view.setVisibility(View.GONE);
first_view.setVisibility(View.VISIBLE);
firstViewOff = false;
}
}
}
Why i attached backpressed:为什么我附上背压:
Because when user backpress then it will just directly show firstview without closing,因为当用户回压时,它只会直接显示 firstview 而不会关闭,
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