如何在 a.txt 文件中流式传输数值并在同一程序中通过 ifstream 读取相同的数据

Question

#include <iostream>
#include <fstream>
using namespace std;
int main()
{
    string mobile;
    int N[10];
    ofstream file;
    file.open("my.txt");
    cout<<"enter mobile ";
    getline(cin, mobile);
    file<<mobile<<endl;
    cout<<"enter number ";
    cin>>N[10];
    file<<N;
    file.close();
    int a;
    cin.ignore();
    cout<<"press 1 to know details ";
    cin>>a;
    if(a==1)
    {
        ifstream file1;
        file1.open("my.txt");
        string str;
        int num;
        file1>>str;
        file1>>num;
        cout<<"company "<<str<<endl<<"number  "<<num;
        file1.close();
    }
    return 0;
}

string value is stored and read perfectly but the integer value entered is stored in the form of 0x61fdf0 and when it is supposed to again print, it always prints 0. I am trying to store a mobile number.

I am coding in code blocks.

Answer 1

#include <iostream>
#include <fstream>
using namespace std;

const int NUM = 10;

int main()
{
    string mobile;
    int n[NUM];
    ofstream file;
    file.open("my.txt");
    cout << "enter mobile: ";
    getline(cin, mobile);
    file << mobile << endl;
    cout << "enter number ";
    file << n[0];
    file.close();
    int a;
    cin.ignore();
    cout << "press 1 to know details ";
    cin >> a;
    if(a==1)
    {
        ifstream file1;
        file1.open("my.txt");
        string str;
        int num;
        (file1, str);
        file1 >> num;
        cout << "company: " << str <<"\nnumber: " << num << endl;
        file1.close();
    }
    return 0;
}