在 Python 3.7.3 中将.txt 文件转换为 integer

Question

I need to turn a.txt file with a single number into a variable with the type 'int'. This is my code so far:

   coinBalance = open.('coinBalance', 'r')

   coinBalance = str(coinBalance)

   coinBalance = int(coinBalance)

And it gives the error: ValueError: invalid literal for int() with base 10: "<_io.TextIOWrapper name='coinBalance' mode='r' encoding='UTF-8'>"

Answer 1

As pointed out by @Moosefeather, you're trying to cast a filepointer to a string and int instead of reading the contents and casting them. The code below will read the contents of the file 'coinBalance' and then cast that string to an int.

coinBalance = int(open('coinBalance').read())