[英]Java initialize map with keys from set
In java, can you initialize a new map's keyset based on the values of an existing set?在 java 中,您可以根据现有集合的值初始化新地图的键集吗?
Something like:就像是:
Set<String> setOfStrings = getSetFromSomeOtherFuntion();
Map<String, Boolean> map = new Hashmap<>(setOfStrings);
If that's possible, then I would presume the value for each entry in the map is null, which is ok, but even better would be if a default value could be set (for example, false if it's Boolean).如果这是可能的,那么我会假设 map 中每个条目的值是 null,这没关系,但如果可以设置默认值(例如,如果它是布尔值则为 false)更好。
Map<K, V> map = new HashMap<>();
setOfStrings.forEach(e -> map.put(e, false));
You can use stream with Collectors.toMap
like so:您可以将 stream 与
Collectors.toMap
一起使用,如下所示:
Map<String, Boolean> map = setOfStrings.stream()
.collect(Collectors.toMap(Function.identity(), v -> false));
If you have to do it in the constructor, you could do something like this:如果您必须在构造函数中执行此操作,则可以执行以下操作:
Set<String> set = new HashSet<String>();
set.add("Key1");
set.add("Key2");
set.add("Key3");
Map<String, Boolean> map = new HashMap<String, Boolean>() {
{
set.forEach(str -> put(str, false));
}
};
System.out.println(map);
Output: Output:
{Key2=false, Key1=false, Key3=false}
However, this method is a little dirty and honestly unnecessary.但是,这种方法有点脏,老实说没有必要。 You might want to see Efficiency of Java "Double Brace Initialization"?
您可能想查看Java“双大括号初始化”的效率?
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