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通过引用 C++ 传递函数数组

[英]passing an array of functions by reference C++

There are multiple functions in a file (let's say file1.h).一个文件中有多个函数(比如说file1.h)。 These functions are similar by their definition and return value.这些函数的定义和返回值相似。 The file itself, it is not allowed to change it.文件本身,不允许更改。 I wanna simplify them like this:我想像这样简化它们:

file1.h文件1.h

int func1 (void)
{
    return 11;
}
int func2(void)
{
    return 12;
}
int func3(void)
{
    return 13;
}

In my source file, which I am allowed to change, I would like to create an array of functions then pass this array by reference to another function, the code here is also simplified:在我允许更改的源文件中,我想创建一个函数数组,然后通过引用另一个 function 来传递这个数组,这里的代码也被简化了:

source_file.cpp源文件.cpp

static int func_main(const int idx, int* arr_of_func)
{
    int ret = 0;
    switch (idx)
    {
        case 1:
            ret = arr_of_func[0];
            break;
        case 2:
            ret = arr_of_func[1];
            break;
        case 3:
            ret = arr_of_func[0];
            break;
        default:
            ret = -1;
            break;
    }

    return ret;
}

int main()
{
    std::cout << "Hello World!\n";
    int x = 0;
    cin >> x;
    int (*arr[3])(void) = {func1, func2, func3};

    cout << func_main(x, *arr);
    system("pause");
}

By invoking the function func_main(x, *arr) I don't know how to pass the array (the second argument).通过调用 function func_main(x, *arr) 我不知道如何传递数组(第二个参数)。 I need your help please.我需要你的帮助。 Thanks.谢谢。

Correct func_main parameter int* arr_of_func to array of function pointers int (*arr_of_func[3])() . func_main参数int* arr_of_func更正为 function 指针int (*arr_of_func[3])()的数组。 Arrays are passed by reference by default. Arrays 默认通过引用传递。

#include <string>
#include <functional>
#include <iostream>

int func1 (void)
{
    return 11;
}
int func2(void)
{
    return 12;
}
int func3(void)
{
    return 13;
}

static int func_main(const int idx, int (*arr_of_func[3])())
{
    int ret = 0;
    switch (idx)
    {
        case 1:
            ret = arr_of_func[0]();
            break;
        case 2:
            ret = arr_of_func[1]();
            break;
        case 3:
            ret = arr_of_func[2]();
            break;
        default:
            ret = -1;
            break;
    }

    return ret;
}

int main()
{
    std::cout << "Hello World!\n";
    int x = 0;
    std::cin >> x;
    int (*arr[3])(void) = {func1, func2, func3};

    std::cout << func_main(x, arr);
    system("pause");
}

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