[英]How to sum nested arrays in JavaScript
I'm trying to create a function that sums the total of all the values in an array, even if those values are nested within nested arrays.我正在尝试创建一个 function,它将数组中所有值的总和相加,即使这些值嵌套在嵌套的 arrays 中。 Like this: countArray(array);像这样:countArray(array); --> 28 (1 + 2 + 3 + 4 + 5 + 6 + 7) I tried this recursive function, but it just concatenates. --> 28 (1 + 2 + 3 + 4 + 5 + 6 + 7) 我试过这个递归 function,但它只是连接起来。
var countArray = function(array){ var sum=0; for(let i=0; i<array.length; i++){ if(array[i].isArray){ array[i]=countArray(array[i]); } sum+=array[i]; } return sum; }
Flatten the array using Array.flat()
, and then sum using Array.reduce()
:使用Array.flat()
平数组,然后使用Array.reduce()
求和:
const countArray = array => array.flat(Infinity).reduce((sum, n) => sum + n, 0) console.log(countArray([1, 2, [3, [4, 5], 6], 7]));
Array.isArray
to check if an object is an array.使用Array.isArray
检查 object 是否为数组。 var countArray = function(array) { var sum = 0; for (let i = 0; i < array.length; i++) { if (Array.isArray(array[i])) { sum += countArray(array[i]); } else { sum += array[i]; } } return sum; } console.log(countArray([1, 2, [3, [4, 5], 6], 7]));
You could also use Array#reduce
with a recursive function.您还可以将Array#reduce
与递归 function 一起使用。
const countArray = array => array.reduce((acc,curr)=> acc + (Array.isArray(curr)? countArray(curr): curr), 0); console.log(countArray([1, 2, [3, [4, 5], 6], 7]));
This problem can be simplified to finding the sum of all elements in a one-dimensional array by using Array#flat
beforehand.这个问题可以简化为通过预先使用Array#flat
来查找一维数组中所有元素的总和。
const countArray = array => array.flat(Infinity).reduce((acc,curr)=>acc+curr, 0); console.log(countArray([1, 2, [3, [4, 5], 6], 7]));
Beside the problem of right application of Array.isArray
, you have an actual use case for taking a named function , because you call the function recursively and by uzsing just a variable, the reference of the function could go. Beside the problem of right application of Array.isArray
, you have an actual use case for taking a named function , because you call the function recursively and by uzsing just a variable, the reference of the function could go.
function countArray(array) {
var sum = 0;
for (const value of array) {
sum += Array.isArray(value) ? countArray(value) : value;
}
return sum;
}
Your working example:您的工作示例:
const arr = [1, [2, [3]]] const countArray = function(array) { let sum = 0; for (let i = 0; i < array.length; i++) { if (Array.isArray(array[i])) { sum += countArray(array[i]); } else { sum += array[i]; } } return sum; } console.log(countArray(arr));
A little bit simplified example:一个简单的例子:
const arr = [1, [2, [3]]] const countArray = (array) => { let sum = 0; for (const el of array) { sum += Array.isArray(el)? countArray(el): el } return sum; } console.log(countArray(arr));
Even more simple code:更简单的代码:
const arr = [1, [2, [3]]] const countArray = (array) => array.reduce((sum, el) => Array.isArray(el)? sum + countArray(el): sum + el, // reduce function 0); // sum = 0 intialization console.log(countArray(arr));
Using ramda:使用 ramda:
const sumNested = compose(sum, flatten) const sumNested = compose(sum, flatten)
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