[英]How to get all the local variables defined inside the function in python?
Is there any way to print all the local variables without printing them expilictly?有没有办法打印所有局部变量而不显式打印它们?
def some_function(a,b):
name='mike'
city='new york'
#here print all the local variables inside this function?
That would be the locals() built-in function那将是locals()内置 function
Python 3.9.0 (tags/v3.9.0:9cf6752, Oct 5 2020, 15:34:40) [MSC v.1927 64 bit (AMD64)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> locals()
{'__name__': '__main__', '__doc__': None, '__package__': None, '__loader__': <class '_frozen_importlib.BuiltinImporter'>, '__spec__': None, '__annotations__': {}, '__builtins__': <module 'builtins' (built-in)>}
>>> x = 5
>>> locals()
{'__name__': '__main__', '__doc__': None, '__package__': None, '__loader__': <class '_frozen_importlib.BuiltinImporter'>, '__spec__': None, '__annotations__': {}, '__builtins__': <module 'builtins' (built-in)>, 'x': 5}
You can filter out the builtins with a list comprehension:您可以使用列表理解过滤掉内置函数:
>>> [_ for _ in locals() if not (_.startswith('__') and _.endswith('__'))]
['x']
If you just want variable names you can use dir() as well:如果你只想要变量名,你也可以使用 dir() :
def some_function(a,b):
name='Mike'
city='New York'
#here print all the local variables inside this function?
print(dir())
some_function()
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