比较数据框 python 中的两列

Question

I have 2 excel files as input.

F1
FileName        Name   Gender
4-F_994637.txt  XXX    Not Identified
4-F_994576.txt  XXX    Not Identified
3-F_977039.txt  XXX    Not Identified
4-F_992516.txt  XXX    Not Identified
3-F_980311.txt  XXX    Not Identified
4-F_994638.txt  XXX    Female
4-F_994126.txt  XXX    Female
3-F_677039.txt  XXX    female
4-F_322516.txt  XXX    male
3-F_677311.txt  XXX    male

F2
FileName        Name   Gender
4-F_994637.txt  XXX    Male
4-F_994576.txt  XXX    Male
3-F_977039.txt  XXX    Male
4-F_992516.txt  XXX    Male
3-F_980311.txt  XXX    Male

All I want is first i need to select "Gender = 'Non Identified'" and compare F1 and F2 with column "FileName" . And if there is match I should replace the Gender in F1 with Male

I tried the below code, but getting error

import pandas as pd

df1=pd.read_excel('F1.xlsx')
df2=pd.read_excel('F2.xlsx')

pick=df1[df1["Gender"]=='Not Identified']
filecompare=pick["FileName"] == df2["FileName"]

ValueError: Can only compare identically-labeled Series objects

Can someone Help what is this error all about.

Thanks, Meera

Answer 1

With pandas version 1.1.1, your code block

pick=df1[df1["Gender"]=='Not Identified']
filecompare = pick["FileName"] == df2["FileName"]
display(filecompare)

returns

You can check for the similar Filenames with the isin() method and set them to 'male' with .loc .

cond_male = (df1['Gender']=='Not Identified') & (df1['FileName'].isin(df2['FileName']))
df1.loc[cond_male,'Gender']='Male'

returns