我将如何使用 find 来收集所有目录的路径，而不是我想要的目录中任何子目录的路径

Question

I'm trying to collect the full pathways of every directory starting with the letter "K" in a large parent directory containing several hundred files and directories. Each of the directories also has subdirectories; the paths of which I don't want. I wanted to list all of my directory pathways in a file called samples.txt. My data is structured like this:

Parent_Directory
|
|__K1
|  |
|  |_Unnecessary_Directory1
|  |
|  |_Unnecessary_Directory2
|
|__K2
|  |
|  |_Unnecessary_Directory1
|  |
|  |_Unnecessary_Directory2
|
K3-K500, Several other unwanted directories/files

I have tried this command and was able to get a samples.txt file with only the paths of the K1-K500 files that I wanted, but I still get the unwanted paths of all of the subdirectories too.

find /Rest/of/Path/Parent_Directory/K* -type d > samples.txt

I tried using -prune as:

find /Rest/of/Path/Parent_Directory/K* -type d -prune -o -name 'Un*' > samples.txt

However, this just left me with an entirely blank samples.txt file. What edits should I make to give me only the K* directories, but not any subdirectories? Thanks in advance!

Answer 1

This should achieve what you wanted:

find /Rest/of/Path/Parent_Directory/K* -type d -prune