问题 state 在 Firestore 中使用开关和 flutter 更改真假

Question

I have a switch which should change state of the user between isOnline or not. this is a bool between true and false. I created a method with cupertino switch:

bool isOnline = true;

the original state is true so the user see they are available online

in the cupertino switch I create a function:

CupertinoSwitch(
                      value: isOnline,
                      onChanged: (bool value) {
                        setState(() {
                          changeState();
                          isOnline = value;
                        });
                      },
                    ),

and I need to update firestore collection:

 CollectionReference changestate = FirebaseFirestore.instance.collection('Consultant');
  Future<void> changeState() {
    var firebaseUser =  FirebaseAuth.instance.currentUser;
    return changestate
        .doc(firebaseUser.uid)
        .update({
      'isOnline': isOnline,
    },)

all works but inside out... when I turn the switch to green it return on the database false and if I turn off it return true any suggestion please?

Answer 1

Issue in your on state code call

isOnline = value;

After

changeState(); 

method.

Like this,

CupertinoSwitch(
    value: isOnline,
      onChanged: (bool value) {
         setState(() { 
           isOnline = value; 
           changeState();      
          }); 
        }, 
      ),