如何通过按键随时跳出循环

Question

I'm on Windows 10, VSCode, Python 3.9

My program is an infinite loop that moves my mouse around the screen. Currently my code allows me to exit the program in between mouse movements, but not mid mouse movement. I want to be able to break at anytime with a keypress.

import time
import pyautogui
import keyboard
pyautogui.FAILSAFE = False
pyautogui.PAUSE = 0
var = 1

while var == 1:

if keyboard. is_pressed('b'):
    break
else:
    pyautogui.moveTo(384, 216, 0.5)

if keyboard. is_pressed('b'):
    break
else:
    pyautogui.moveTo(1536, 216, 0.5)

if keyboard. is_pressed('b'):
    break
else:
    pyautogui.moveTo(1536, 864, 0.5)

if keyboard. is_pressed('b'):
    break
else:
    pyautogui.moveTo(384, 864, 0.5)

This is my first question on here so please let me know if my formatting is wrong. Also if anyone has recommendations to make my code prettier I will gladly accept.

Answer 1

As mentioned in comments, threading is a good way to go:

import threading
import time
import keyboard

def move_mouse(arg):    # simulate a blocking function call, like pyautogui.moveTo()
    print("moving {}".format(arg))
    time.sleep(arg)

def loop_through_moves():
    while True:
        move_mouse(1)
        move_mouse(2)
        move_mouse(3)

t = threading.Thread(target=loop_through_moves)
t.daemon = True
t.start()

while True:
    if keyboard. is_pressed('b'):
        break

Answer 2

If you want to exit on ctrl-C you can use a try: except: call like this:

import sys
import time
import pyautogui
import keyboard
pyautogui.FAILSAFE = False
pyautogui.PAUSE = 0
var = 1

try:
    while var == 1:
        if keyboard. is_pressed('b'):
            break
        else:
            pyautogui.moveTo(384, 216, 0.5)
        
        if keyboard. is_pressed('b'):
            break
        else:
            pyautogui.moveTo(1536, 216, 0.5)
        
        if keyboard. is_pressed('b'):
            break
        else:
            pyautogui.moveTo(1536, 864, 0.5)
        
        if keyboard. is_pressed('b'):
            break
        else:
            pyautogui.moveTo(384, 864, 0.5)
except KeyboardInterrupt:
    sys.exit()

This way should allow you to exit the program by pressing ctrl-C AKA `KeyboardInterrupt``

PS: Ctrl-C should auto kill your program but this does that!