[英]Snowflake JSON FLATTEN with ORDER BY
I have a working query that flattens a nested JSON object into rows of data.我有一个工作查询,将嵌套的 JSON object 展平为数据行。 What I would like to do, however, is preserve the original order of one array of objects which is nested several layers in.
然而,我想做的是保留一个对象数组的原始顺序,该对象数组嵌套在多个层中。
I have tried to use ROW_NUMBER
with an ORDER BY NULL
and an ORDER BY (SELECT NULL)
and neither seem to preserve the order.我尝试将
ROW_NUMBER
与ORDER BY NULL
和ORDER BY (SELECT NULL)
一起使用,但似乎都没有保留顺序。
Any ideas on how to accomplish that?关于如何实现这一目标的任何想法? Examples below.
下面的例子。 I chose to mask the real data, but the important parts of the structure are the same.
我选择屏蔽真实数据,但结构的重要部分是相同的。 The data in JSON format comes through with no rank-identifying information, but I used numbers as examples here to show the strange results.
JSON 格式的数据没有排名识别信息,但我在这里使用数字作为示例来显示奇怪的结果。
Original structure (masked):原始结构(屏蔽):
{
"topNode: {
"childNode": {
"list": [
{
"title": "example title 1",
},
{
"title": "example title 2",
},
{
"title": "example title 3",
},
{
"title": "example title 4",
},
{
"title": "example title 5",
}
]
}
}
}
Example query (masked):示例查询(屏蔽):
SELECT
A.VALUE:"title"::VARCHAR AS "TITLE",
ROW_NUMBER() OVER(ORDER BY NULL) AS RANK
FROM
DB.SCHEMA.TABLE as A,
lateral flatten(input=>A.JSON:topNode.childNode.list) "list_flatten"
Example output:示例 output:
TITLE RANK
"example title 3" 1
"example title 5" 2
"example title 2" 3
"example title 1" 4
"example title 4" 5
It is possible with INDEX
, which returns index of element in array: INDEX
是可能的,它返回数组中元素的索引:
SELECT A.VALUE:"title"::VARCHAR AS "TITLE",
"list_flatten".index AS "RANK"
FROM DB.SCHEMA.TABLE as A,
lateral flatten(input=>A.JSON:topNode.childNode.list) "list_flatten"
I have a working query that flattens a nested JSON object into rows of data.我有一个工作查询将嵌套的 JSON object 展平为数据行。 What I would like to do, however, is preserve the original order of one array of objects which is nested several layers in.
但是,我想做的是保留嵌套了几层的一组对象的原始顺序。
I have tried to use ROW_NUMBER
with an ORDER BY NULL
and an ORDER BY (SELECT NULL)
and neither seem to preserve the order.我尝试将
ROW_NUMBER
与ORDER BY NULL
和ORDER BY (SELECT NULL)
一起使用,但似乎都没有保留订单。
Any ideas on how to accomplish that?关于如何做到这一点的任何想法? Examples below.
下面的例子。 I chose to mask the real data, but the important parts of the structure are the same.
我选择屏蔽真实数据,但结构的重要部分是相同的。 The data in JSON format comes through with no rank-identifying information, but I used numbers as examples here to show the strange results.
JSON 格式的数据没有排名识别信息,但我在这里使用数字作为示例来显示奇怪的结果。
Original structure (masked):原始结构(屏蔽):
{
"topNode: {
"childNode": {
"list": [
{
"title": "example title 1",
},
{
"title": "example title 2",
},
{
"title": "example title 3",
},
{
"title": "example title 4",
},
{
"title": "example title 5",
}
]
}
}
}
Example query (masked):示例查询(屏蔽):
SELECT
A.VALUE:"title"::VARCHAR AS "TITLE",
ROW_NUMBER() OVER(ORDER BY NULL) AS RANK
FROM
DB.SCHEMA.TABLE as A,
lateral flatten(input=>A.JSON:topNode.childNode.list) "list_flatten"
Example output:示例 output:
TITLE RANK
"example title 3" 1
"example title 5" 2
"example title 2" 3
"example title 1" 4
"example title 4" 5
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