查找与列表匹配的子字符串

Question

How do I find all the substrings matching a df column value?

text = "The quick brown fox jumps over the lazy dog"
df = pd.DataFrame(['quick brown fox', 'jump', 'lazy dog', 'banana', 'quick fox'], columns=['value'])
results = get_matches(df, text)
# Excepted results: ['quick brown fox', 'jump', 'lazy dog']

Answer 1

One option:

import pandas as pd

text = "The quick brown fox jumps over the lazy dog"
df = pd.DataFrame(['quick brown fox', 'jump', 'lazy dog', 'banana', 'quick fox'], columns=['value'])


def get_matches(df, text):
    return df[df['value'].apply(text.__contains__)]


res = get_matches(df, text)
print(res)

Output

             value
0  quick brown fox
1             jump
2         lazy dog

As an alternative, use str.find :

def get_matches(df, text):
    return df[df['value'].apply(text.find).ne(-1)]


res = get_matches(df, text)
print(res)

Output

             value
0  quick brown fox
1             jump
2         lazy dog

Answer 2

Try:

def get_matches(df, text): 
    return df.loc[[t in text for t in df['value']], 'value']

get_matches(df, text)

Output:

0    quick brown fox
1               jump
2           lazy dog
Name: value, dtype: object

Answer 3

List=[]
for a in df.value:
    if a in text:
        print(a)
        List.append(a)
print(List)