尝试从 Django 表单运行 python 脚本

Question

I am creating a simple ui which takes 2 files as input and if we press submit button then trying to run script.py (which is Python script) and render output on screen or some output folder我正在创建一个简单的用户界面，它需要 2 个文件作为输入，如果我们按下提交按钮，然后尝试运行 script.py（这是 Python 脚本）并在屏幕上或某些 Z78E6221F6393D1356Z81DBCE63 上渲染 output

#forms.py #forms.py

from django import forms
class AwsForm ( forms.Form ):
    Aws_SourceFile = forms.FileField ()
    Aws_RefernceFile = forms.FileField ()

#views.py #views.py

from django.shortcuts import render
from .forms import AwsForm
import subprocess

def home_view(request):
    context = {}
    context [ 'form' ] = AwsForm ()
    return render ( request , "home.html" , context )

def submit_view(request):
    info = request.POST [ 'info' ]


def my_view(request):
    if request.method == 'GET':
        form = AwsForm ()
    else:
        if form.is_valid ():
            info = request.POST [ 'info_name' ]
            output = script_function ( info )
            return render ( request , 'myapp/home.html' , {
                'info': info ,
                'output': output ,
            } )
    return render ( request , 'myapp/home.html' , {
        'form': form ,
    } )


def script_function(post_from_form):
    print ( post_from_form )
    return subprocess.check_call ( [ '\script_18122020.py' , post_from_form ] )

#urls.py #urls.py

from django.contrib import admin
from django.urls import path
from myapp.views import home_view, submit_view

urlpatterns = [
    path('', home_view ),
    path('submit', submit_view),

]

#home.html #home.html

{% block main_content %}
<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <meta http-equiv="X-UA-Compatible" content="ie=edge">
    <title>Homepage</title>
</head>
<body>
    <h1>Welcome to Adwait Algorithm and Aws.</h1>
    <form method="POST" enctype="multipart/form-data">
        <form action="your_view_url" method="post">
    {% csrf_token %}
    {{ form.as_p}}
    <input type="submit" value="Submit">
    </form>

<p> Post Data: {{ info }} </p>
<p> Result: {{ output }} </p>
{% endblock main_content %}

</body>
</html>

I am trying to pickup a script and I want to display the output to a folder or on html file or on screen.我正在尝试获取脚本，并且我想将 output 显示到文件夹或 html 文件或屏幕上。

Answer 1

You will have to alter your script function to accept 2 files.您必须更改脚本 function 以接受 2 个文件。 Also change in your template...还要更改您的模板...

<form action="your_view_url" method="post">

to至

 <form action="my_view" method="post">

Add my_view to your urls.py将 my_view 添加到您的 urls.py

forms.py edit these 2 lines forms.py 编辑这两行

Aws_SourceFile = forms.FileField(upload_to='your_directory_name/')
Aws_RefernceFile = forms.FileField(upload_to='your_directory_name/')

Views.py.. (my_view) # You need to pass the exact location of your files to the script Views.py.. (my_view) # 您需要将文件的确切位置传递给脚本

Aws_SourceFile = request.FILES.get('Aws_SourceFile')
Aws_RefernceFile =request.FILES.get('Aws_RefernceFile')

ASF_dir_file = os.path.join('your_directory_name', Aws_SourceFile.uploadfile.name)

ARF_dir_file = os.path.join('your_directory_name', Aws_RefernceFile.uploadfile.name)


output = script_function ( ASF_dir_file, ARF_dir_file )

def script_function(ASF_dir_file, ARF_dir_file):
    
    output_asf = subprocess.check_call ( [ '\script_18122020.py' , ASF_dir_file] )
    output_asr = subprocess.check_call ( [ '\script_18122020.py' , ARF_dir_file] )
     
    return output_asf, output_asf

尝试从 Django 表单运行 python 脚本

问题描述

1 个解决方案

解决方案1
0 2020-12-23 09:46:23

尝试从 Django 表单运行 python 脚本

问题描述

1 个解决方案

解决方案1 0 2020-12-23 09:46:23

解决方案1
0 2020-12-23 09:46:23