python 中的字符串内的按位运算

Question

s = "1 ^ 0 ^ 1 ^ 1 & 0 | 1 "

How to perform the operation in s if s is a string in python?

my problem is to replace a with bitwise and, b with bitwise or, and c with bitwise or and perform the action.

k = '1C0C1C1A0B1'
alpha = []
for i in range(len(k)):
    p = k[i]
    alpha.append(p)

for i in range(len(alpha)):
    if alpha[i] == 'A':
        alpha[i] = '&'
    if alpha[i] == 'B':
        alpha[i] = '|'
    if alpha[i] == 'C':
        alpha[i] = '^'

s = " ".join(map(str, alpha))
print(s)

i tried this above code i don't know how to proceed further. Please help me.

Answer 1

You can use eval command.

Python's eval() is an incredibly useful tool, the function has some important security implications that you should consider before using it. https://realpython.com/python-eval-function/

k = '1C0C1C1A0B1'
s = k.replace('A', '&').replace('B', '|').replace('C','^')
eval(s)
# output : 1

security checking with regex

import re
regex = r"^((0|1)[A-C])*(0|1)$"
k = '1C0C1C1A0B1'

# Input control
match = re.match(regex, k)
if not match:
    raise Exception("Input format error") 


s = k.replace('A', '&').replace('B', '|').replace('C','^')
eval(s)
# output : 1