如何从用户输入替换列表中的某个字符串？

Question

I made a list which contains a number of names and a menu with options that the user can use to alter the list. One of the options is to replace one of the names in the list with whatever the user inputs. How can this be done? I prefer to not use indexes

My code so far:

print("==================")
names = ["Chris", "Dave", "Joseph", "Harvey", "Levi"]
print(names)
print("==================")

print("(A) Add a name \n(B) Change a name \n(C) Delete a name \n(D) View all names \n(Q) Quit ")
print("==================")

while True:

    choice = input("Select an option: ").lower()

    if choice == "a":
        newName = input("Enter a new name: ")
        names.append(newName)

    elif choice == "b":
        oldName = input("What name would you like to replace?: ")
        newName = input("Enter a new name: ")

        # I don't know what to put here
    

    elif choice == "c":
        delete = input("Which name do you want to remove?: ")
        names.remove(delete)

    elif choice == "d":
        print(names)

    elif choice == "q":
        print("Goodbye")
        break

Answer 1

It really would be a good idea to use index here, and you can look up the specific index at the time the user looks it up.

elif choice == "b":
    oldName = input("What name would you like to replace?: ")
    newName = input("Enter a new name: ")

    i = names.index(oldName)
    names[i] = newName

It would also be useful to add validation to make sure that the app doesn't crash when a name is entered that isn't in the list. Something like:

if oldName in names:
    i = names.index(oldName)
    names[i] = newName
else:
    print("That name is not in the list")

The same validation could be added to the delete option.

Answer 2

    elif choice == "b":
        oldName = input("What name would you like to replace?: ")
        newName = input("Enter a new name: ")
        names = [x if x != oldName else newName for x in names ]
        print(names)

You can use a list comprehension to add the names if the name does not equal oldName , if the name does equal oldName then add the newName instead.