发现相似元素时如何终止程序

Question

I have the following 2D list:

test_list = [['A', 'B', 'C'], ['I', 'L', 'A', 'C', 'K', 'B'], ['J', 'I', 'A', 'B', 'C']]

I want to compare the 1st list elements of the 2D array test_list[0] with all other lists. If the elements ['A', 'B', 'C'] are present in all other lists then it should print any message such as "All elements are similar" and the program should terminate when it finds the above condition

I have tried this piece of code but it only needs a termination condition: this is only a best-case scenario in which all elements are present.

test_list = [['A', 'B', 'C'], ['I', 'L', 'A', 'C', 'K', 'B'], ['J', 'I', 'A', 'B', 'C']]

s = test_list[0]
for e in test_list[1:]:
    if all(v in e for v in s):
        print(e, "contains all elements of ", s)

#the program should terminate only if all the members are present.

Answer 1

You can use another all() call to test all of test_list[1:]

s = test_list[0]
if all(all(v in e for v in s) for e in test_list[1:]):
    print("All elements are similar")