[英]Printing a table or list from a complex php array
I have an array that is generated from a third party.我有一个由第三方生成的数组。 Which means I must work with the array format I have been given.
这意味着我必须使用我得到的数组格式。 Below is an array extract from var_dump.
下面是从 var_dump 中提取的数组。
{
[0]=> object(stdClass)#3510 (3) {
["privacy"]=> string(1) "0"
["name"]=> string(11) "jumpsuits"
["token"]=> string(12) "PD21B62AIFFM"
}
[1]=> object(stdClass)#3509 (3) {
["privacy"]=> string(1) "1"
["name"]=> string(8) "helmets"
["token"]=> string(12) "PL68C79RKYAP"
}
}
I am not a php programmer.我不是 php 程序员。 But I do need to find a simple way in PHP to turn the array data in the format above into a three column table with the headings 'privacy', 'name' and 'token'.
但我确实需要在 PHP 中找到一种简单的方法,将上述格式的数组数据转换为一个三列表,标题为“隐私”、“名称”和“令牌”。
If I could just get a starter for ten as to why echo $array['name'][0]
returns nothing I think I could work the rest out.如果我能得到一个关于为什么
echo $array['name'][0]
什么都不返回的 10 的入门,我想我可以解决 rest。
Thank you谢谢
<?php
$array = json_decode(json_encode($object), true); // convert array of object to assoc array
//all array:
var_dump(array_column($array, 'privacy')); //privacy as array
var_dump(array_column($array, 'name')); //name as array
var_dump(array_column($array, 'token')); //token'
//specific data:
$data['privacy'] = array_column($array, 'privacy');
$data['name'] = array_column($array, 'name');
$data['token'] = array_column($array, 'token');
echo $data['name'][0];
//etc
Is an array of objects, so you can loop it like this;是一个对象数组,所以你可以像这样循环它;
<?php
echo '<table>';
echo '<tr>';
echo '<td>';
echo 'Privacy';
echo '</td>';
echo '<td>';
echo 'Name';
echo '</td>';
echo '<td>';
echo 'Token';
echo '</td>';
echo '<tr>';
foreach($data as $row) {
echo '<tr>';
echo '<td>';
echo $row->privacy;
echo '</td>';
echo '<td>';
echo $row->name;
echo '</td>';
echo '<td>';
echo $row->token;
echo '</td>';
echo '<tr>';
}
echo '</table>';
Check it in codepad http://codepad.org/MhcaKKRP在键盘上查看http://codepad.org/MhcaKKRP
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