指针指向哪里？

Question

This is the defination for my class.

class RingBuffer {
private:
    static const size_t buffer_size;
public:
    
    std::shared_ptr<RingBufferLock> ring1_;
    std::shared_ptr<RingBufferLock> ring2_;
    RingBuffer();

};

I take a pointer out of the class object:

std::shared_ptr<RingBuffer> rings = std::make_shared<RingBuffer>();

Do the value of rings.get() function call is the same as the value of rings_->ring1_.get() function call?

Answer 1

rings.get() :

This is getting raw pointer from rings which gives you RingBuffer *

rings_->ring1_.get() :

I suppose you mean rings->ring1_.get() , which first dereferences rings and then get raw pointer from member ring1_ . It is the same with rings.get()->ring1_.get() . The final result is a RingBufferLock *