我如何使用正则表达式获取两个字符内的字符串并删除该字符串内的某些字符

Question

I have a long string that I want to filter using regex

<@961483653468439706> Text to remove, this text is useless, that's why i want it gone!
i want this: `keep the letters and spaces`

I want to keep the text that in-between the ` characters

only issue is that in-between every character in the part of the string I want there is an invisible character. you can see the invisible characters in regex101: https://regex101.com/r/rAYrMT/1

`([\'^\w]*)`

So in short: keep everything between ` except for the invisible characters info on which can be found here: https://apps.timwhitlock.info/unicode/inspect?s=%EF%BB%BF

Answer 1

You can filter the non printable characters out:

import re 
from string import printable

# your invisibles are in the string...

s='''<@961483653468439706> Text to remove, this text is useless, that's why i want it gone!
Type `keep the letters and spaces` and `this too`'''

for m in re.findall(r'`([^`]*)`', s):
    print(repr(m))
    print(''.join([c for c in m if c in printable]))
    print()

Prints:

'k\ufeffe\ufeffe\ufeffp\ufeff \ufefft\ufeffh\ufeffe\ufeff \ufeffl\ufeffe\ufefft\ufefft\ufeffe\ufeffr\ufeffs a\ufeffn\ufeffd s\ufeffp\ufeffa\ufeffc\ufeffe\ufeffs'
keep the letters and spaces

'this too'
this too

Answer 2

You don't need to use regex for this:

text = "<@961483653468439706> Text to remove, this text is useless, that's " \
       "why i want it gone!Type `keep the letters and spaces`"

# put your invisible character between the first quotation marks here. obviously, they
# don't show up in this post.
filtered = text.replace('', '')
# because the passage you want is always between ``, you can split it and know that every
# second item in the list that split returns must be what you are looking for. 
passage = filtered.split('`')[::2]

print(passage)