R 使用 formattable 更改数据框 / HTML 表中文本的颜色

Question

I would like to add different colour text to a date frame or HTML table based on the following rules (which able to time to crack variable)

instant = red text, seconds = orange text, minutes - yellow text, years = green text.

My data frame is

> dput(Final_DF)
structure(list(gender = c("female", "male", "male", "female", 
"female", "male", "male", "male", "male", "female", "male", "male", 
"female", "female", "female", "female", "male", "female", "male", 
"male", "female", "female", "female", "female", "female", "female", 
"male", "female", "female", "female", "female", "female", "female", 
"female", "male", "male", "female", "female", "male", "female", 
"female", "male", "female", "female", "male", "male", "male", 
"male", "male", "male"), age = structure(c(47L, 43L, 65L, 24L, 
44L, 60L, 26L, 25L, 62L, 23L, 44L, 61L, 27L, 47L, 18L, 23L, 34L, 
77L, 71L, 19L, 64L, 61L, 22L, 55L, 45L, 29L, 21L, 64L, 43L, 20L, 
32L, 55L, 68L, 21L, 81L, 43L, 63L, 72L, 38L, 20L, 66L, 39L, 64L, 
20L, 73L, 21L, 53L, 75L, 69L, 82L), class = c("variable", "integer"
), varname = "Age"), web_browser = structure(c(1L, 1L, 4L, 1L, 
3L, 3L, 2L, 1L, 4L, 1L, 1L, 1L, 3L, 4L, 1L, 2L, 1L, 3L, 3L, 2L, 
1L, 1L, 1L, 3L, 4L, 3L, 4L, 4L, 1L, 2L, 1L, 1L, 3L, 1L, 1L, 2L, 
1L, 2L, 3L, 4L, 2L, 3L, 1L, 1L, 1L, 1L, 3L, 3L, 4L, 1L), .Label = c("Chrome", 
"Internet Explorer", "Firefox", "Netscape"), class = c("variable", 
"factor"), varname = "Browser"), Pswd = c("Password", "abc1", 
"football", "Pr?hStMz3xuJ", "Strawberries", "JTA9SsTLjU", "Jazzed!", 
"D!gU4", "12345!", "mQf0J?2", "password1", "CATS?", "F!!FtBm", 
"!!!!", "HBpqA?xya9SIi", "Os4Ft%D", "fryj0t9KS", "monkey", "shadow", 
"gpbvYZxYLBq7P", "blackberries", "Abc1!", "p0$YpH4", "SLOTH", 
"Qwertyuiop", "SqbmZZ!abHj", "?Lnp6X6TNz", "boatstatecat", "shearer9", 
"1B!aKnQm", "JTA9SsTLjU", "DOGS", "sunshine", "pgJz8!Hdde", "qwerty", 
"1q2w3e4r5t", "flightrockcups", "ashley", "Htkv5TDS51", "C8cFMWH?a$S", 
"cheesesteak", "password!", "aircraft", "Se3PKKeg?dU", "iloveyou", 
"Bug!5$r", "123", "dragon", "superman", "password"), pswd_length = c(8L, 
4L, 8L, 12L, 12L, 10L, 7L, 5L, 6L, 7L, 9L, 5L, 7L, 4L, 13L, 7L, 
9L, 6L, 6L, 13L, 12L, 5L, 7L, 5L, 10L, 11L, 10L, 12L, 8L, 8L, 
10L, 4L, 8L, 10L, 6L, 10L, 14L, 6L, 10L, 11L, 11L, 9L, 8L, 11L, 
8L, 7L, 3L, 6L, 8L, 8L), Time_to_crack = c("instant", "instant", 
"instant", "857 billion years", "0.84 seconds", "0.02 seconds", 
"4.71 seconds", "5.46 minutes", "instant", "111 years", "instant", 
"6.11 seconds", "23 days", "0.1 seconds", "393 million years", 
"3 months", "49 years", "instant", "instant", "81 trillion years", 
"43.7 seconds", "19.62 seconds", "12 years", "1.58 seconds", 
"0.15 seconds", "23 thousand years", "2 million years", "11 hours", 
"5.81 seconds", "1 year", "4 thousand years", "0.09 seconds", 
"instant", "4 million years", "instant", "0.34 seconds", "23 hours", 
"instant", "41 centuries", "14 thousand years", "11.26 seconds", 
"instant", "0.3 seconds", "8 thousand years", "instant", "4 hours", 
"instant", "instant", "instant", "instant")), row.names = c(NA, 
-50L), class = "data.frame")

I have found this formatable data frame walkthrough, but not sure how to apply it to my scenario

Answer 1

This could be achieved like so:

1. Following the vignette define a formatter function using ifelse or using eg dplyr::case_when which defines the conditional styles to apply.
2. In formattable apply this formatter to your column Time_to_crack

    library(formattable)
    library(dplyr)
    
    time_formatter <- formatter("span", 
                                style = x ~ style(color = dplyr::case_when(
                                  grepl("(instant|seconds)", x) ~ "red",
                                  grepl("(months|years)", x) ~ "green", 
                                  grepl("hours", x) ~ "yellow", 
                                  grepl("minutes", x) ~ "orange",
                                  TRUE ~ "black")))
    
    formattable(Final_DF, list(Time_to_crack = time_formatter))