如何打破循环 onClick ReactJS

Question

I have a function that does some animation using async await() . I want to play/pause the animation onClick . I used useState to update the variable but the function is not behaving as I want. While the const print () is running and when I click on the button, text updates, but the function doesn't break. In the log, "play" is printed 100 times. I'm guessing useState and async is causing something. How can I solve this?

const Test= props => {

    const [ButtonText, SetButtonText] = useState("Play");
    const ToggleButtonText = () => {
        if(ButtonText == "Play")          
            SetButtonText("Pause")

        if(ButtonText == "Pause")
            SetButtonText("Play")
    }

    const delay = ms => new Promise(res => setTimeout(res, ms));

    const print= () => {
        for(var i = 0; i < 100; i++)        
        {
            ///
               work
               await delay(1000);
               work
            ///
           console.log(ButtonText);
           
           if(ButtonText == "Pause")
               break ; 

        }
    };
    return (
           <div>
              <div>
                   ///work component///
              </div>
            <button onClick = {() => ToggleButtonText()}> {ButtonText}</button>
           </div>
    )
}

Answer 1

The ButtonText is declared as const - it can't change its value inside a given call of the functional component.

Without more info, I'd use a ref as well as state, so that the loop can see if the ref gets changed:

const buttonTextRef = useRef();
// Update the ref to ButtonText every time ButtonText changes:
useEffect(() => {
  buttonTextRef.current = ButtonText;
}, [ButtonText]);

if (buttonTextRef.current === 'Pause') {
  break;
}

Another method would be to put the index being iterated over into state, and instead of looping 100 times, re-render 100 times, eg, something along the lines of:

const [printI, setPrintI] = useState(0);
if (printI) {
  // Then we're in the middle of iterating
  // work
  if (printI < 100) {
    setTimeout(() => {
      setPrintI(printI + 1);
    }, 1000);
  } else {
    setPrintI(0);
  }
};

and to stop it, call setPrintI(0) .