查询以计算超过 24 小时间隔的时间总和

Question

I have time like 25:00:00, 10:00:00, 30:00:00 and I want to calculate the sum of the values from database. How can I do that the current query for calculating sum is

SQL query:

SELECT 
    CAST(FORMAT((SUM((DATEPART("ss", Total_Time) + 
           DATEPART("mi", Total_Time) * 60 + 
           DATEPART("hh", Total_Time) * 3600)) / 3600), '00') AS varchar(max)) + ':' + CAST(FORMAT((SUM((DATEPART("ss", Total_Time) + DATEPART("mi", Total_Time) * 60 + DATEPART("hh", Total_Time) * 3600)) % 3600 / 60), '00') as varchar(max)) + ':' +CAST(FORMAT((SUM((DATEPART("ss", Total_Time) + DATEPART("mi", Total_Time) * 60 + DATEPART("hh", Total_Time) * 3600)) % 3600 % 60), '00') as varchar(max)) as WorkingTimeSum 
FROM 
    tasker_usr.TaskTime

but I get an error

Cannot convert from datetime to character string

Answer 1

You cannot fit your values into a time datatype. It stores only value less than 23:59:59.9999999 . Hence you cannot use DATEPART or DATEDIFF directly. One way is to split your values( as seconds ) and do the sum. Something like

WITH CTE_SUM
AS (
    SELECT SUM(LEFT(column_name, 2) * 3600 
               + SUBSTRING(column_name, 4, 2) * 60 
               + SUBSTRING(column_name, 7, 2)) AS SUM_AS_SECONDS
    FROM YOUR_TABLE
    )
SELECT CAST(SUM_AS_SECONDS / 3600 AS VARCHAR) + ':' 
       + CAST(SUM_AS_SECONDS % 3600 / 60 AS VARCHAR) + ':' 
       + CAST(((SUM_AS_SECONDS % 3600) % 60) AS VARCHAR) AS WorkingTimeSum
FROM CTE_SUM

Please note that this will work upto 99:99:99 .If you have time values that are more than that, then you have to split based on : instead of hardcoding values in LEFT/Substring

Answer 2

Are you looking something like this?

Declare @Hours Table(Hrs VARCHAR(20))
Declare @Hour TINYINT, @Minute INT,@Second INT, @InSeconds BIGINT, @Cdate DATETIME

INSERT @Hours
SELECT '25:00:00' Union All
SELECT '10:00:00' Union All
SELECT '30:00:00'

select @Hour = sum(cast(Left(Hrs,CharIndex(':',Hrs,1)-1) as int)) from @Hours

select @Minute = sum(cast(Substring(Hrs,CharIndex(':',Hrs,1)+1,2)as int)) from @Hours

select @Second = sum(cast(Substring(Hrs,CharIndex(':',Hrs,1)+4,2)as int)) from @Hours

Set @InSeconds = @Second + (@Minute * 60) + (@Hour *60 *60)

Set @Cdate = dateadd(second,@InSeconds,0)

select datediff(day,'1900-01-01',@Cdate) [Day(s)],
Format(@Cdate,'hh') [Hour(s)],
Format(@Cdate,'mm') [Minute(s)],
Format(@Cdate,'ss') [Second(s)]

Day(s)	Hour(s)	Minute(s)	Second(s)
2	05	00	00

Answer 3

Assuming that your format is HH(n):MM:SS (that is, hours can have 1 or more digits), you can decompose the value and reconstruct it. This requires string functions. You can get the total seconds as:

select sum(left(total_time, charindex(':', total_time) - 1) * 60 * 60 +
           left(right(total_time, 5), 2) * 60 +
           right(total_time, 2)
          ) as total_secs
from tasker_usr.TaskTime;

Note: This does implicit conversion from the string values to integers, but that should be okay if your values are consistent.

You can convert back to string:

select concat(format(total_secs / (60 * 60), '00:'), 
              format( (total_secs / 60) % 60, '00:'),
              format(total_secs % 60, '00')
             ) as time_format
from (select sum(left(total_time, charindex(':', total_time) - 1) * 60 * 60 +
                 left(right(total_time, 5), 2) * 60 +
                 right(total_time, 2)
                ) as total_secs
     from tasker_usr.TaskTime
    ) t