具有特定模式的元组列表

Question

Is there a way to create a list of tuples with a certain pattern? I want to have the following list without having to manually write them all, I think it may be "easy" since there is kind of a pattern in the tuple list, but not sure how to do it.

a = [
[(30, 5, 10),
(30, 5, 20),
(30, 5, 30),
(30, 10, 10),
(30, 10, 20),
(30, 10, 30),
(30, 20, 10),
(30, 20, 20),
(30, 20, 30)],

[(35, 5, 10),
(35, 5, 20),
(35, 5, 30),
(35, 10, 10),
(35, 10, 20),
(35, 10, 30),
(35, 20, 10),
(35, 20, 20),
(35, 20, 30)],

[(40, 5, 10),
(40, 5, 20),
(40, 5, 30),
(40, 10, 10),
(40, 10, 20),
(40, 10, 30),
(40, 20, 10),
(40, 20, 20),
(40, 20, 30)]
    ]
a

Output:

[[(30, 5, 10),
  (30, 5, 20),
  (30, 5, 30),
  (30, 10, 10),
  (30, 10, 20),
  (30, 10, 30),
  (30, 20, 10),
  (30, 20, 20),
  (30, 20, 30)],
 [(35, 5, 10),
  (35, 5, 20),
  (35, 5, 30),
  (35, 10, 10),
  (35, 10, 20),
  (35, 10, 30),
  (35, 20, 10),
  (35, 20, 20),
  (35, 20, 30)],
 [(40, 5, 10),
  (40, 5, 20),
  (40, 5, 30),
  (40, 10, 10),
  (40, 10, 20),
  (40, 10, 30),
  (40, 20, 10),
  (40, 20, 20),
  (40, 20, 30)]]

Answer 1

Yes, using the range function , with step.

range(start, stop, step)

A simple way of doing this is like this:

array = []

for x in range(30, 45, 5):
    y_tuple_multipler = 1
    sub_array = []
    for y in range(1, 4):
        y_tuple = 5 * y_tuple_multipler
        for z in range(10, 40, 10):
            sub_array.append((x, y_tuple, z))
        y_tuple_multipler *= 2
    array.append(sub_array)
print(array)

You can probably get more pythonic , but simplicity is always good (and easier to debug multiple loops)

Answer 2

You can try this list comprehensions:

l1 =[30,35,40]
l2 =[5,10,20]
l3= [10,20,30] 

l =  [[(i1,i2,i3) for i2 in l2 for i3 in l3 ]for i1 in l1]

If you want to add number just add it to the inner tuple (for exmaple, 10):

l =  [[(10,i1,i2,i3) for i2 in l2 for i3 in l3 ]for i1 in l1]